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miss Akunina [59]
3 years ago
12

What does anhydrous mean in your own words?

Chemistry
2 answers:
dalvyx [7]3 years ago
4 0

Answer: no water

Explanation:

egoroff_w [7]3 years ago
4 0

Answer:

a substance that is a crystalline compound, contains no water

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Electrochemistry might be considered a subspecialty of which of the following areas of chemistry
riadik2000 [5.3K]
Hey there!

<span> Electrochemistry might be considered a subspecialty of which of the following areas of chemistry?

Answer: </span>
<span>D. Organic chemistry

Hope this helps
Have a great day (:
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3 0
3 years ago
A certain compound contains 4.0 g of calcium and 7.1 g of chlorine. Its relative molecular mass is 111. Find its empirical and m
Phantasy [73]

Given :

A certain compound contains 4.0 g of calcium and 7.1 g of chlorine.

Its relative molecular mass is 111.

To Find :

Its empirical and molecular formulas.

Solution :

Moles of calcium , n_1=\dfrac{4}{40}=0.1\ moles.

Moles of chlorine , n_2=\dfrac{7.1}{35.45}=0.2\ moles .

The ratio calcium and chlorine is 1 : 2 .

So , the empirical formula is CaCl_2 .

Now , molecular mass of CaCl_2 is :

M=40+(2\times 35.45)\\\\M=110.9\ g

So , n=\dfrac{111}{110.9} \approx1

Therefore , the molecular formula is also CaCl_2 .

Hence , this is the required solution .

7 0
2 years ago
Use the balanced equation from number four above to determine the limiting reactant if we had a mixture of 5.0 moles of Fe and 4
Tom [10]

Answer:

2Fe + 3O₂  →  2Fe₂O₃

Limiting reactant: O₂

2Fe + O₂ → 2FeO

Limiting reactant: Fe

Explanation:

2Fe + 3O₂  →  2Fe₂O₃

2Fe + O₂ → 2FeO

These are the possible reactions:

In first case, 2 moles of Fe need 3 mol of oyxgen to react

If I have 5 moles of Fe, I will need (5 .3)/2 = 7.5 moles of O₂

Then, the oxygen is my limiting ( I only have 4 moles)

3 moles of O₂ need 2 moles of Fe

If I have 4 moles of O₂, I will need (4 .2)/3 = 2.66 moles (I have 5)

Fe, is the reactant in excess.

For second case, 2 moles of Fe need 1 mol of O₂, to react.

If I have 5 moles of Fe, I will need ( 5 .1) / 2 =2.5 moles of O₂

I have 4 moles of oxygen, so now it is my excess.

1 mol of O₂ need 2 moles of Fe, to react

If I have 4 moles of O₂, I will need the double of amount, 8 moles of Fe.

I have 5 moles, then the Fe is my limtiing reactant.

8 0
2 years ago
Calculate the volume in milliliters of a 1.27 mol/L silver perchlorate solution that contains 125.mmol of silver perchlorate (Ag
Lunna [17]

Answer:

This solution has a volume of 98.4 mL

Explanation:

Step 1: Data given

Molarity of AgClO4 solution = 1.27 mol/L

Number of moles AgClO4 = 125 mmol = 0.125 mol

Molar mass of AgClO4= 207.32 g/mol

Step 2: Calculate volume of the 1.27 M solution

Molarity = moles / volume

Volume = moles / molarity

Volume = 0.125 moles / 1.27 mol /L

Volume = 0.0984 L = 98.4 mL

This solution has a volume of 98.4 mL

7 0
3 years ago
3. Round the number 10.4656 to the tenths place *<br><br> 10 <br><br> 10.4 10.5 or 10.6
motikmotik
Answer: 10.5 hope this helps!
5 0
2 years ago
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