Mass = number of mol x molar mass
Mass = 0.28mol x 55.8g/mol
Mass = 15.624g
Answer:
0.35 atm
Explanation:
It seems the question is incomplete. But an internet search shows me these values for the question:
" At a certain temperature the vapor pressure of pure thiophene (C₄H₄S) is measured to be 0.60 atm. Suppose a solution is prepared by mixing 137. g of thiophene and 111. g of heptane (C₇H₁₆). Calculate the partial pressure of thiophene vapor above this solution. Be sure your answer has the correct number of significant digits. Note for advanced students: you may assume the solution is ideal."
Keep in mind that if the values in your question are different, your answer will be different too. <em>However the methodology will remain the same.</em>
First we <u>calculate the moles of thiophene and heptane</u>, using their molar mass:
- 137 g thiophene ÷ 84.14 g/mol = 1.63 moles thiophene
- 111 g heptane ÷ 100 g/mol = 1.11 moles heptane
Total number of moles = 1.63 + 1.11 = 2.74 moles
The<u> mole fraction of thiophene</u> is:
Finally, the <u>partial pressure of thiophene vapor is</u>:
Partial pressure = Mole Fraction * Vapor pressure of Pure Thiophene
- Partial Pressure = 0.59 * 0.60 atm
Answer:
half-life of 5,700 ± 40 years
Explanation:
Answer:
1. not affected by a magnet 1 liquid
2. mostly space 2 solid
3. flows freely but particles still attract 3 proton
4. positively charged particles 4 gas
5. free to move in all space 5 alpha particles
6. negatively charged particles 6 atoms
7. atoms nearly fixed in space 7 gamma ray 8. helium nucleus 8 electron (beta)
U would subtract 90 minus 45 which equals 45