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GenaCL600 [577]
2 years ago
11

What are the distinguishing features of each extraction process: pyrometallurgy, electrometallurgy, and hydrometallurgy? Explain

briefly how the types of metallurgy are used in the production of(a) Fe;
Chemistry
1 answer:
Tatiana [17]2 years ago
7 0
<h3>1.Pyrometallurgy</h3>
  • This techniques involves the high temperature at which the Chemical reactions took place between the gases and solids.
  • Pyrometallurgy involves calcination, Roasting and smelting process.

 

<h3>  2.Electrometallurgy</h3>
  • This technique involves the metallurgy operations that took place in electrolytic cell.
  • Electro- winning and Electro-refining are some of the electrometallurgy process

<h3>   3. Hydrometallurgy</h3>
  • Reactions involves aqueous solutions to extract metal, use this technique.
  • Hydrometallurgy involves precipitation , distillation , adsorption and solid extraction operations.

Now,

Type of metallurgy are used in the production of Fe is Roasting and Smelting.

<h3>What is Roasting?</h3>
  • Ore is heated strongly with other substances, usually with Oxygen.
  • Process temperature is below the melting point.
  • Some of Impurities is removed as volatile substance.

In this reaction,

 FeO changes to Fe₂O₃ to prevent the loss of iron during smelting.

4FeO +O₂→ Fe₂O₃.

Now,

<h3>   What is Smelting?</h3>
  • The oxides of less electropositive metals like Pb, Zn, Fe, Sn, etc.
  • These are reduced by strongly heating with coal or coke.
  • Reduction of the oxide with Carbon at high temperature is known as Smelting.

Thus from the above conclusion we can say that , metallurgy are used in the production of Fe is Roasting and Smelting.

Learn more about Iron here: brainly.com/question/2535311

#SPJ4

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Answer:

70g

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If you react 2.00 g of hydrogen completely using 15.87 g of oxygen to produce water, how much water (in grams) will you have?
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Answer:

The amount (mass) of water we will have is 17.869 grams

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15.87 g of O₂ will give;

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Therefore 0.9921 moles of H₂ will react with 0.9921/2 or 0.49595 moles of O₂ to produce 0.9921 moles of H₂O

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