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GenaCL600 [577]
1 year ago
11

What are the distinguishing features of each extraction process: pyrometallurgy, electrometallurgy, and hydrometallurgy? Explain

briefly how the types of metallurgy are used in the production of(a) Fe;
Chemistry
1 answer:
Tatiana [17]1 year ago
7 0
<h3>1.Pyrometallurgy</h3>
  • This techniques involves the high temperature at which the Chemical reactions took place between the gases and solids.
  • Pyrometallurgy involves calcination, Roasting and smelting process.

 

<h3>  2.Electrometallurgy</h3>
  • This technique involves the metallurgy operations that took place in electrolytic cell.
  • Electro- winning and Electro-refining are some of the electrometallurgy process

<h3>   3. Hydrometallurgy</h3>
  • Reactions involves aqueous solutions to extract metal, use this technique.
  • Hydrometallurgy involves precipitation , distillation , adsorption and solid extraction operations.

Now,

Type of metallurgy are used in the production of Fe is Roasting and Smelting.

<h3>What is Roasting?</h3>
  • Ore is heated strongly with other substances, usually with Oxygen.
  • Process temperature is below the melting point.
  • Some of Impurities is removed as volatile substance.

In this reaction,

 FeO changes to Fe₂O₃ to prevent the loss of iron during smelting.

4FeO +O₂→ Fe₂O₃.

Now,

<h3>   What is Smelting?</h3>
  • The oxides of less electropositive metals like Pb, Zn, Fe, Sn, etc.
  • These are reduced by strongly heating with coal or coke.
  • Reduction of the oxide with Carbon at high temperature is known as Smelting.

Thus from the above conclusion we can say that , metallurgy are used in the production of Fe is Roasting and Smelting.

Learn more about Iron here: brainly.com/question/2535311

#SPJ4

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nasty-shy [4]

Answer:

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Explanation:

3 0
3 years ago
What happens to an object at rest if balanced forces act upon it?
OLga [1]

Newton's first law of motion states that an object at rest will remain at rest unless an unbalanced force acts on it. If you apply balanced forces on the object there would be no net force. The body does not accelerate but instead stays at rest.

Another way to look at this problem is to use Newton's second law of motion. The first law states that F = m\times a, where a is the accelerationF is the net force and m is the mass of the object.

When F is zero, the acceleration of the object is zero. This means that if the object had a velocity of zero before the balanced forces started acting, the velocity will stay at zero after the balanced forces begin to act. If  the object was moving at a constant velocity before the balanced forces started acting on it, it would continue at that constant velocity after the balanced forces begin to act.

4 0
2 years ago
I need help ASAP!!!!! What happens to water when it changes to ice?
Gre4nikov [31]

- It's density increases

- mass increases

- volume increases

Hope this helps!

6 0
2 years ago
Read 2 more answers
How much heat is added if .0948g of water is increased in temperature by .728 degrees C?
Verdich [7]

Answer:

0.289J of heat are added

Explanation:

We can relate the change in heat of a substance with its increasing in temperature using the equation:

q = m*ΔT*S

<em>Where Q is change in heat</em>

<em>m is mass of substance (In this case, 0.0948g of water)</em>

<em>ΔT = 0.728°C</em>

<em>S is specific heat (For water, 4.184J/g°C)</em>

Replacing:

q = 0.0948g*0.728°C*4.184J/g°C

q = 0.289J of heat are added

5 0
2 years ago
You have 345 mL of a 2.5 M NaCl solution. If you boil the water until the volume of the solution is 250 mLwhat will the molarity
HACTEHA [7]

The molarity of the solution will be 3.45 M

<h3>Further explanation </h3>

Dilution is the process of adding a solvent to get a more dilute solution.

The moles(n) before and after dilution are the same.

Can be formulated :

M₁V₁=M₂V₂  

M₁ = Molarity of the solution before dilution  

V₁ = volume of the solution before dilution  

M₂ = Molarity of the solution after dilution  

V₂ = Molarity volume of the solution after dilution

The initial solution

345 mL of a 2.5 M NaCl solution.

M₁=2.5 M

V₁=345 ml

The solution after boiled :

V₂=250 ml

\tt M_2=\dfrac{M_1.V_1}{V_2}\\\\M_2=\dfrac{2.5\times 345}{250}\\\\M_2=3.45~M

5 0
2 years ago
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