First calculate the initial moles of HCl.
HCl moles i = (1.45 moles / L) * 0.5 L = 0.725 moles HCl
Then calculate how much HCl is consumed by stoichiometry:
HCl moles consumed = (12.7 g Zn / 65.38 g / mol) * (2
moles HCl / 1 mole Zn) = 0.388 moles
So HCl moles left is:
HCl moles f = 0.725 – 0.388 = 0.3365 moles
For every 1 mole HCl there is 1 mole H, therefore:
H moles final = 0.3365 moles
So final concentration of H ions is:
<span>Concentration H = 0.3365 moles / 0.5 L = 0.673 M</span>
Answer : The 
for this reaction is, -88780 J/mole.
Solution :
The balanced cell reaction will be,
Here, magnesium (Cu) undergoes oxidation by loss of electrons, thus act as anode. silver (Ag) undergoes reduction by gain of electrons and thus act as cathode.
The half oxidation-reduction reaction will be :
Oxidation : 
Reduction : 
Now we have to calculate the Gibbs free energy.
Formula used :
where,
= Gibbs free energy = ?
n = number of electrons to balance the reaction = 2
F = Faraday constant = 96500 C/mole
= standard e.m.f of cell = 0.46 V
Now put all the given values in this formula, we get the Gibbs free energy.
Therefore, the for this reaction is, -88780 J/mole.
They would be found in shallow rivers because it would be easiest for them to find there food in a shallow river. and i go fishing so i know
1) is the answer because the only way to turn it from blue to yellow is to mix it with an acidic solution.
