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Ket [755]
3 years ago
13

3) A rather large fish is about to eat an unsuspecting small fish. The big fish has a mass of 5kg and is

Physics
1 answer:
Rashid [163]3 years ago
5 0

Answer:

the velocity of the big fish after the launch is 6 m/s.

Explanation:

Given;

mass of the big fish, m₁ = 5 kg

velocity of the big fish, u₁ = 8 m/s

mass of the small fish, m₂ = 1 kg

velocity of the small fish, u₂ = -4 m/s

Let the final velocity of the big fish after launch = v

Apply the principle of conservation linear momentum;

m₁u₁ + m₂u₂ = v(m₁ + m₂)

5 x 8   + 1 x (-4) = v(5 + 1)

40 - 4 = 6v

36 = 6v

v = 36/6

v =  6 m/s.

Therefore, the velocity of the big fish after the launch is 6 m/s.

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If I wanted to generate a maximum emf of 20 V, what angular velocity (radians/sec, aka Hz) would be required given a circular co
MissTica

Answer:

35.36776 Hz

Explanation:

B = Magnetic field = 9\times 10^{-3}}\ T

E_m = Maximum voltage = 20 V

d = Diameter of coil = 40 cm = 0.4 m

A = Area = \pi \frac{d}{2}^2=\pi 0.2^2

N = Number of turns = 500

\omega = Angular velocity

Maximum emf is given by

E_m=NAB\omega\\\Rightarrow \omega=\frac{E_m}{NAB}\\\Rightarrow \omega=\frac{20}{500\times \pi\times 0.2^2\times 9\times 10^{-3}}\\\Rightarrow \omega=35.36776\ Hz

The angular velocity would be 35.36776 Hz

8 0
4 years ago
A man walke towards the bus stop 100 meters away at a constant velocity. He reaches the bus stop in 200 seconds. Once at the bus
serg [7]
First:

d = 100 m
t = 200 sec

v = 100/200 = 0.5 m/s

Displacement is zero since he returned to his start point.

t2 = d/v2 = 100/2 = 50 sec

total time = 50 + 200 + 500 = 750 sec
3 0
4 years ago
If.<br> a. Substance is. A mineral , how. Could. U identity. What. Types. Of. Mineral. It. Is
Luden [163]
You could look under a microscope it see what type of minerals they have or substances they have that makes them one .!
4 0
3 years ago
Can someone help me?!!!!!
SOVA2 [1]

Answer:magnitude -5; angle 160°

Explanation:

Vector A is described as having magnitude 5 and angle -20°.

To get an equivalent vector, we either leave the magnitude at 5 and add 360° to the angle, or we reverse the magnitude to -5 and add 180° to the angle.

5 @ -20° = 5 @ 340°

5 @ -20° = -5 @ 160°

The third one is the answer.

8 0
4 years ago
A) Is it possible for an object that, object with zero acceleration have velocity? If yes give an example if not give its proof.
sveticcg [70]

Answer:

Yes, in case of uniform velocity

Explanation:

This is the case of uniform velocity. If a body covers equal displacement in equal intervals of time, then the velocity of a body is said to be ‘Uniform Velocity’. It meas that the velocity of a body remains constant during the motion and it does not change.

Since, acceleration is defined as the rate of change of velocity.

Therefore, if there is no change in velocity or in other words the change in velocity is zero, then the acceleration is also zero.

a = ΔV/t = 0/t

a = 0 m/s²

So, the acceleration of the body is 0 m/s², but it has a uniform velocity

<u>Hence, it is possible for an object that, object with zero acceleration have velocity, which is the case case of uniform velocity.</u>

7 0
3 years ago
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