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pochemuha
3 years ago
10

Can someone help me pls

Physics
1 answer:
Dmitry_Shevchenko [17]3 years ago
4 0
First question: 800J
Second question: 20.4m
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Two masses of size m and 4m are connected by a massless thread and are strung over a frictionless pulley of radius R and moment-
tekilochka [14]

Answer:

Total kinetic energy of entire system is 3 mgl

Explanation:

Given two masses: m and 4m.

Since the pulley is frictionless and the thread is massless, the energy here is linked to the two masses.

Total kinetic energy of entire system = decrease in gravitational potential energy of the system.

Therefore, we have :

ΔKE = Δp

ΔKE = 4mgl - mgl

= 3 mgl

Total kinetic energy of entire system is 3 mgl

6 0
3 years ago
If the results of a study do not support a hypothesis, it means that experiment failed
butalik [34]
No that is incorrect. If the results do not support the hypothesis than the hypothesis could have been incorrect. Or there is a possibility that the experiment was not done properly. A hypothesis is an educated guess for the results of the experiment. 
6 0
4 years ago
A uniform rod of mass 2.30 kg and length 2.00 m is capable of rotating about an axis passing through its center and perpendicula
melomori [17]

Answer:

Explanation:

Moment of inertia of the rod = 1/12 m L²

m is mass of the rod and L is its length

= 1/2 x 2.3 x 2 x 2

= 4.6 kg m²

Moment of inertia of masses attached with the rod

= m₁ d² + m₂ d²

m₁ and m₂ are masses attached , and d is their distance from the axis of rotation

= 5.3 x 1² + 3.5 x 1²

= 8.8 kg m²

Total moment of inertia = 13.4 kg m²

B )

Rotational kinetic energy = 1/2 I ω²

I is total moment of inertia and ω is angular velocity

= .5 x 13.4 x 2²

= 26.8 J .

C )

when mass of rod is negligible , moment of inertia will be due to masses only

Total moment of inertia of masses

= 8.8 kg m²

D )

kinetic energy of the system

= .5 x 8.8 x 2²

= 17.6 J .

3 0
4 years ago
A person is standing on a level floor. His head, upper torso, arms, and hands together weigh 496 N and have a center of gravity
Mandarinka [93]

Answer: 1.09 m

Explanation:

Given

Weight of the body, W1 = 496 N

Weight of his upper legs, W2 = 199 N

Weight of his lower legs, W3 = 81.2 N

Center of gravity of the body, y1 = 1.37 m

Center of gravity of the upper legs, y2 = 0.711 m

Center of gravity of the lower legs, y3 = 0.284 m

Center of gravity relative to the floor, y(f) = ?

y(f) = (W1y1 + W2y2 + W3y3) / (W1 + W2 + W3), substituting the values, we have

y(f) = [(496 * 1.37) + (199 * 0.711) + (81.2 * 0.284)] / (496 + 199 + 81.2)

y(f) = (679.52 + 141.489 + 23.0608) / 776.2

y(f) = 844.0698 / 776.2

y(f) = 1.09 m

3 0
3 years ago
Once a player catches the Frisbee they are only allowed to pivot like in
Natasha_Volkova [10]
True I know from pe hahahahha
5 0
3 years ago
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