Complete question
A 2700 kg car accelerates from rest under the action of two forces. one is a forward force of 1157 newtons provided by traction between the wheels and the road. the other is a 902 newton resistive force due to various frictional forces. how far must the car travel for its speed to reach 3.6 meters per second? answer in units of meters.
Answer:
The car must travel 68.94 meters.
Explanation:
First, we are going to find the acceleration of the car using Newton's second Law:
(1)
with m the mass , a the acceleration and 
the net force forces that is:
(2)
with F the force provided by traction and f the resistive force:
(2) on (1):
solving for a:
Now let's use the Galileo’s kinematic equation
(3)
With Vo te initial velocity that's zero because it started from rest, Vf the final velocity (3.6) and 
the time took to achieve that velocity, solving (3) for :
Answer:
W = 343.2 J
Explanation:
Given that,
Mass of bale of hay = 26 kg
Horizontal force exerted = 88 N
Distance moved, d = 3.9 m
Work done, W = Fd
Put all the values,
W = 88 N × 3.9 m
= 343.2 J
So, the work done is 343.2 J.
Answer:
4.53482 m/s
4.506 m/s
Explanation:
= Mass of player = 75 kg
= Initial velocity of player = 4.6 m/s
= Mass of ball = 0.47 kg
= Initial velocity of ball = 15 m/s
The linear momentum of the system is conserved
The player's speed is 4.53482 m/s
In the second case the equation of momentum is
The player's speed is 4.506 m/s
Answer:
By teh way is isn't it question of law or science and the picture is of what electric light or not I have read it so I was asking isn't is question of science
