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atroni [7]
4 years ago
9

Compare the wavelength and energy of ultraviolet rays to visible light

Chemistry
1 answer:
Nadusha1986 [10]4 years ago
6 0

Answer:

Visible wavelengths range from 0.0007 milimeters for red light, through orange, yellow, green, and blue, to 0.0004 milimeters for violet light.

Ultraviolet is shorter wavelengths than violet.

Hope This Helps.

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The magnet below is cut in half. What will be the result
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the cut pieces will have their own north and south pole

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2 years ago
Read 2 more answers
How many moles are in 3.01 x 10 atoms of magnesium
Fiesta28 [93]
There are 3.01 moles. round to 3 if it asks for a whole number 
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3 years ago
What is a reaction rate?
kondaur [170]

Answer:

A reaction rate is a measure of how fast a reactant disappears or a product forms during a reaction.

Explanation:

It is usually defined as the change in concentration per unit time:

Δ(concentration)/Δt

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7 0
4 years ago
(part 1 of 3) Copper reacts with silver nitrate through a single replacement. If 1.29 g of silver are produced from the reaction
ale4655 [162]

Answer:

See explanation.

Explanation:

Hello there!

In this case, according to the described chemical reaction, we first write the corresponding equation to obtain:

Cu+2AgNO_3\rightarrow 2Ag+Cu(NO_3)_2

Thus, we proceed as follows:

Part 1 of 3: here, since the molar mass of silver and copper (II) nitrate are 107.87 and 187.55 g/mol respectively, and the mole ratio of the former to the latter is 2:1, we can set up the following stoichiometric expression:

m_{Cu(NO_3)_2}=1.29gAg*\frac{1molAg}{107.87gAg}*\frac{1molCu(NO_3)_2}{2molAg}*\frac{187.55gCu(NO_3)_2}{1molCu(NO_3)_2}   \\\\m_{Cu(NO_3)_2}=1.12gCu(NO_3)_2

Part 2 of 3: here, the molar mass of copper is 63.55 g/mol and the mole ratio of silver to copper is 2:1, the mass of the former that was used to start the reaction was:

m_{Cu}=1.29gAg*\frac{1molAg}{107.87gAg}*\frac{1molCu}{2molAg}*\frac{63.55gCu)_2}{1molCu}   \\\\m_{Cu}=0.380gCu

Part 3 of 3: here, the molar mass of silver nitrate is 169.87 g/mol and their mole ratio 2:2, thus, the mass of initial silver nitrate is:

m_{AgNO_3}=1.29gAg*\frac{1molAg}{107.87gAg}*\frac{2molAgNO_3}{2molAg}*\frac{169.87gAgNO_3}{1molAgNO_3}   \\\\m_{AgNO_3}=2.03gAgNO_3

Best regards!

5 0
3 years ago
A single human body cell typically contains thousands of
Nitella [24]
The answer to your question should be genes. 

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3 years ago
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