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kirill115 [55]
3 years ago
8

Imagine that you could dive deep into the Atlantic Ocean where the South American plate and African plate meet at a plate bounda

ry. What do you think you would see at the plate boundary? Would you see the mantle? Why or why not?
Chemistry
1 answer:
Alex787 [66]3 years ago
4 0

Answer:

At the plate boundary, there would be a divergent boundary where we can see a mid ocean ridge and a gap. We would be able to see the mantle because there would be a fissure from where magma will rise and solidify.    

Explanation:

Under the South American plate and African plate, there are currents that cause a divergent boundary. They create this boundary since they pull the tectonic plates apart, causing a mid-ocean ridge with an opening that allows the rising of the magma that was underneath. Once that the magma is out, it solidifies, and the currents will try to create another ridge to repeat the process.

When the plates are apart, the mantle that is beneath is exposed, and we can see the magma.

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A particular reaction, a → products, has a rate that slows down as the reaction proceeds. the half-life of the reaction is found
irga5000 [103]
Generally, the rate of a reaction will decrease with increasing temperature, although there are some exceptions in the case of non-elementary reactions. However it is more likely that the first statement is false.
Half-life is a measure of the time taken for a to reach 1/2 of its initial concentration, and is generally completely independent of reagent concentration within a first order reaction, which is likely what this reaction is, therefore statement 2 is also likely false.
Hope this helps!
8 0
4 years ago
suppose you use a pitcher to to estimate 1.25 qt of water ( experimental volume) . You later measured the volume more precisely
saul85 [17]

The percent error in the initial measurement would be 6.47%

<h3>Percent Error</h3>

Percent error in any measurement is mathematically given as:

                    absolute error/true measurement x 100%

In this case;

True measurement = 1.34 qt

Absolute Error = 1.34 - 1.25

                         = 0.09 qt

Percent error = 0.09/1.34 x 100%

                      = 6.47%

More on percent error can be found here: brainly.com/question/3105259?referrer=searchResults

6 0
3 years ago
Name the element which lies in group IA and 3rd period. What is the valency of it and why?​
Jlenok [28]

Answer:

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4 0
3 years ago
Read 2 more answers
A metal in group 1 of the periodic table can become a chemically stable ion by
Mkey [24]
Bonding ionically with a group 7 non-metal
4 0
4 years ago
15.0 mL of 0.050 M Ba(NO3)2 M and 100.0 mL of 0.10 M KIO3 are added together in a 250 mL erlenmeyer flask. In this problem, igno
timama [110]

Answer:

Yes, precipitation of barium iodate will occur.

Explanation:

Molarity of barium nitrate solution = 0.050 M

Volume of barium nitrate solution =15.0 mL = 0.0150 L

1 mL = 0.001 L

Moles of barium nitrate = n

n=0.050 M\times 0.0150L=0.00075 mol

Ba(NO_3)_2(aq)\rightarrow Ba^{2+}(aq)+2NO_3^{-}(aq)

Moles of barium ions: 1\times 0.00075 mol=0.00075 mol

Molarity of potassium iodate solution = 0.10 M

Volume of potassium iodate solution =100.0 mL = 0.1000 L

1 mL = 0.001 L

Moles of potassium iodate = n'

n'=0.10 M\times 0.1000 L=0.01 mol

KIO_3(aq)\rightarrow K^{+}(aq)+IO_3^{-}(aq)

Moles of iodate ions = 1\times 0.01 mol=0.01 mol

After mixing of both solution in 250 mL in erlenmeyer flask

Volume of the final solution = 250 mL = 0.250 L

Concentration of barium ions in 250 mL solution :

[Ba^{2+}]=\frac{0.00075 mol}{0.250 L}=0.003 M

Concentration of iodate ions:

[IO_3^{-}]=\frac{0.01 mol}{0.250 L}=0.04 M

Solubility product of barium iodate,K_{sp}=4.01\times 10^{-9}

Ionic product of the barium iodate in solution :K_i

Ba(IO_3)_2\rightleftahrpoons Ba^{2+}+2IO_3^{-}

K_i=[Ba^{2+}][IO_2^{-}]^2

K_i=0.003 M\times (0.04 M)^2=4.8\times 10^{-6}

K_{sp}  ( precipitation)

As we can see, the ionic product of the barium iodate is greater than the solubility product of the barium iodate precipitation of barium iodiate will occur in 250 mL of final solution.

5 0
3 years ago
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