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4 years ago

Question 4 (1 point)

Physics

1 answer:

NNADVOKAT [17]4 years ago

6 0

Answer: 0.42 Amperes

Explanation:

Given that:

Current, I = ?

Electric charge Q = 100 coulomb

Time, T = 4.0 minutes

(The SI unit of time is seconds. so, convert 4.0 minutes to seconds)

If 1 minute = 60 seconds

4.0 minutes = 4.0 x 60 = 240 seconds

Since electric charge, Q = current x time

i.e Q = I x T

100 coulomb = I x 240 seconds

I = 100 coulomb / 240 seconds

I = 0.4167 Amperes (round to the nearest hundredth which is 0.42 amperes)

Thus, 0.42 Amperes of current flows in the circuit.

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The concentration of carbon monoxide in an urban apartment is 48 Î¼g/m3. What mass of carbon monoxide in grams is present in a r

Vedmedyk [2.9K]

Answer:

The answer is 3213.6 grams.

Explanation:

In meters the room dimensions are 3.05-3.2-6.86.

Total volume of the room is:

$3.05*3.2*6.86=66.95$

66.95 m3.

The density of carbon monoxide is 48 g/m3. Then total grams is present in a room measuring:

$66.95*48=3213.6$

8 0

4 years ago

To illustrate the use of a multistage rocket consider the following:

garri49 [273]

Answer:

$v_f = 0.916 v_{ex}$

$v_f = 1.05 v_{ex}$

Explanation:

Considering question a

From the question we are told that

The mass of the rocket is $m_o$

The mass of the fuel which is in the rocket is m = 0.6 M

Generally given that the rocket burns all it fuel in a single stage , the final velocity of the rocket is mathematically represented as

$v_f = v_{ex} ln [\frac{m_o}{m_k} ]$

Here $m_k$ is the mass of the rocket without fuel which is mathematically evaluated as

$m_k = m_o- m$

=> $m_k = m_o -0.6m_o$

=> $m_k = [1- 0.6] m_o$

=> $v_f = v_{ex} ln [\frac{m_o}{[1 - 0.6]m_o} ]$

=> $v_f = 0.916 v_{ex}$

Considering question b

From the question we are told that

The mass of the fuel it burn at the first stage is $m = 0.3 m_o$

The mass of the first stage fuel tank $m_1 = 0.1 m_o$

The mass of the fuel at the second stage is $m_f = 0.3m_o$

Generally the velocity of the rocket at the first stage is mathematically represented as

$v_i = v_{ex} * ln [ \frac{m_o }{[1- m]m_o } ]$

=> $v_i = v_{ex} * ln [ \frac{m_o }{[1- 0.3]m_o } ]$

=> $v_i = v_{ex} * ln [ \frac{1 }{0.7 } ]$

=> $v_i =0.357 v_{ex}$

Generally the mass of the rocket after first stage is

$m_r = m_o - 0.3m_o -0.1m_o$

=> $m_r = 0.6m_o$

Generally the final velocity of the rocket at the second stage is

$v_f = v_i + v_{ex} * ln [\frac{m_r}{ m_f } ]$

=> $v_f = v_i + v_{ex} * ln [\frac{0.6 m_o }{0.3mo } ]$

=> $v_f = 0.357 v_{ex} + 0.693 v_{ex}$

=> $v_f = 1.05 v_{ex}$

4 0

3 years ago

ASAP pls answer right and I will mark brainiest

Ronch [10]

1. D:Asteroids have geological activity
2.A:Short-period comets circle around the sun in 200 years or less and originate in the Kuiper Belt
3.D:All of the above
4.A:It’s gravity is too weak to clear it’s orbit
5.B:Ceres
6.C:Haumea
7.A:Is bigger than Pluto

I hope this helps

6 0

3 years ago

A vertical scale on a spring balance reads from 0 to 250 N. The scale has a length of 15.0 cm from the 0 to 250 N reading. A fis

lesantik [10]

Answer:

Mass of fish=6.252 kg

Explanation:

Force F=0 N to 250 N

Length x=15.0 cm=0.15 m

Frequency f=2.60 Hz

To find

Mass of fish m

Solution

First we need to find spring constant

$k=Force/distance\\k=F/x\\k=250/0.15\\k=1666.7 N/m$

As we know that the time period is given as

$T=2\pi\sqrt{\frac{m}{k} }\\ And\\f_{Frequency} =1/T\\So\\1/f=2\pi\sqrt{\frac{m}{k} }\\1/f^{2}=4\pi^{2}\frac{m}{k}\\ k/f^{2}=4\pi^{2}m\\m=\frac{k}{4\pi^{2}f^{2} } \\m=\frac{1666.7}{4\pi^{2} (2.60)^{2} }\\ m=6.252kg$