Answer:
5 trips
Step-by-step explanation:
Note that the weight and volume of the load must not exceed the given maximum.
Volume of load = 19.8m^3
Density of load = 650kg/m^3
Mass of load = 19.8 × 650 = 12,870 kg
Given limits.
Volume = 4m^3
Mass = 3700kg
Assuming the truck is to carry 4m^3 of the load.
The mass of 4m^3 of the load is = 4 × 650 = 2600kg
Mass = 2600kg < 3700kg
Therefore it satisfies both conditions.
The number of trip the truck would make is;
N = total volume of load/ volume per trip
N = 19.8/4
N = 4.95
N = 5 trips
Answer:
1536 in^2
Step-by-step explanation:
This is basically asking for the surface area so knowing that is a cube all the sides are equal so one side would be 16(16) which is 256 in ^2. The knowing that there is 6 sides you would multiply it by 6 which is 256(6)= 1536^2
Use bodmas/pemdas rule
4^3*(4)-5^0
64*4-1 anything to the power zero is one
256-1
255
Answer:
thats facts bro
Step-by-step explanation:
thats facts
I believe the normal distribution is symmetrical above and below
the mean. That tells us that in this kind of distribution, the mean
and the median are the same number ... 50% of the population
is below it, and 50% is above it.
So if the female Labs' weight actually follows a 'normal' distribution
with a mean of 62.5 lbs, then 2,700 of them weigh more than 62.5 lbs
and 2,700 of them weigh less than that.
The standard deviation doesn't matter.