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3 years ago

Scientists are studying animals in a large lake area. In this lake area, both owls and raccoons eat ducks, and ducks eat frogs.

Chemistry

1 answer:

Stolb23 [73]3 years ago

5 0

Answer:

Population of duck and frog will change with the change

Explanation:

The complete question is

Scientists are studying animals in a large lake area. In this lake area, both owls and raccoons eat ducks, and ducks eat frogs. The data shows that recently the size of the raccoon population decreased. How will the decrease in the raccoon population affect the other populations? Be sure to explain whether the owl population, the duck population, and the frog population will change, and why.

Owl population will change
Duck population will change
Frog population will change

Solution

Raccoon eat duck and duck eat frog. Now if the population of Raccoon decreases then the number of predators of duck will decrease thereby increasing the population of duck.

The higher will be the number of ducks, the more frogs they will consume thereby decreasing the population of frogs

Hence both the population of duck and frog will change with the change

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1. Bonds are created between elements with different electronegativity, most bonds would be polar. Bonds in NO3 are polar.

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3. Nitrate (NO3-)ion geometry would be trigonal planar

For CCl4 molecule(fig.2)

1. Bonds are created between elements with different electronegativity, most bonds would be polar. Bonds in CCl4 are polar.

2. It is a completely symmetrical molecule.

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1. Bonds are created between elements with different electronegativity, most bonds would be polar. Bonds in NH3 molecule are polar.

2. it has a pyramidal structure.

3. the individual N-H bond dipoles don't cancel out. This dipole moment for the molecule indicates that NH3 is a polar molecule

For SF6 molecule(fig.4)

1.F is more electronegative than S. So the bonds are polar.

2. The symmetry of the molecule is symmetrical so that the dipole moments of bonds cancel correspond so the molecule is non-polar.

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The solution you identified in question (1) acts as a buffer due to reactions that occur within the solution when an acid or a b

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Answer:

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Explanation:

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$CH_3COONa\ (aq) + HCl\ (aq)\longrightarrow CH_3COOH\ (aq) + NaCl\ (aq)\\\\$

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$CH_3COO^{-} \ (aq) + H^{+}\ (aq) \longrightarrow CH_3COOH \ (aq)$

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