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weeeeeb [17]
4 years ago
15

A student evaluates a weight loss program by calculating the number of times he would need to climb a 14.0 m high flight of step

s in order to lose one pound (0.45 kg) of fat. Metabolizing 1.00 kg of fat can release 3.77 x 10' 1 of chemical energy and the body can convert about 22.0% of this into mechanical energy (the rest goes into internal energy.)(a) How much mechanical energy (in 3) can the body produce from 0.450 kg of fat?_______.(b) How many trips up the flight of steps are required for the 68.0 kg student to lose 0.450 kg of fat? Ignore the relatively small amount of energy required to return down the stairs_______trips.
Physics
1 answer:
Liula [17]4 years ago
7 0

Answer:

400 trips

Explanation:

Mechanical energy needed to climb 14 m by a man of 68 kg

= mgh

= 68 x 9.8 x 14

= 9330 J

1 Kg of fat releases 3.77 x 10⁷ J of energy

.45 kg of fat releases 1.6965 x 10⁷ J of energy

22% is converted into mechanical energy

so 22% of 1.6965 x 10⁷ J

= 3732.3 x 10³ J of mechanical energy will be available for mechanical work.

one trip of climbing of 14 m requires 9330 J of mechanical energy

no of such trip possible with given mechanical energy

= 3732.3 x 10³ / 9330

= 400 trips

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(125\ m)^2+ (125\ m)^2=31250 m^2

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The volume of cylinder,

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4 0
3 years ago
A particle leaves the origin with a speed of 3.6 106 m/s at 34 degrees to the positive x axis. It moves in a uniform electric fi
Andrej [43]

Answer:

E = -4556.18 N/m

Explanation:

Given data

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Question)

from the projectile motion the horizontal distance traveled by electron is

x = u×cosA×t

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We also know that force in an electric field is given as

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By newton 2nd law of motion

ma = qE

⇒a = qE/m

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if y = 0 then

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Now plugging the values we get

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4 0
3 years ago
A hockey stick strikes a hockey puck of mass 0.17 kg. If the force exterted on the hockey puck is 35.0 N and there is a force of
GREYUIT [131]

Answer:

a=190\ m/s^2

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Net force, F=F'-f

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