The distance covered by the object between t =4 s and t = 6 s is 4 m
Explanation:
In a velocity-time graph, the distance covered by the object represented can be found by calculating the area under the curve.
Therefore, the distance covered by the object between t = 4 s and t = 6 s is the area under the curve between 4 s and 6 s.
We see that we have to calculate the area of a triangle, with:
Base:
And height:
Therefore, the area is
So, the distance covered by the object is 4 m.
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Answer:
P = 800 Pa
Explanation:
The pressure of water at the bottom of the pot can be given by the following formula:
where,
P = Pressure at the bottom of the pot = ?
ρ = density = 1000 kg/m³
h = height of water = 8 cm = 0.08 m
Therefore,
<u>P = 800 Pa </u>
Gravity is directly proportional to the product of the two. Masses and inversely proportional to the square distance between the two masses.
Either 175 N or 157 N depending upon how the value of 48° was measured from.
You didn't mention if the angle of 48° is from the lug wrench itself, or if it's from the normal to the lug wrench. So I'll solve for both cases and you'll need to select the desired answer.
Since we need a torque of 55 N·m to loosen the nut and our lug wrench is 0.47 m long, that means that we need 55 N·m / 0.47 m = 117 N of usefully applied force in order to loosen the nut. This figure will be used for both possible angles.
Ideally, the force will have a 0° degree difference from the normal and 100% of the force will be usefully applied. Any value greater than 0° will have the exerted force reduced by the cosine of the angle from the normal. Hence the term "cosine loss".
If the angle of 48° is from the normal to the lug wrench, the usefully applied power will be:
U = F*cos(48)
where
U = Useful force
F = Force applied
So solving for F and calculating gives:
U = F*cos(48)
U/cos(48) = F
117 N/0.669130606 = F
174.8537563 N = F
So 175 Newtons of force is required in this situation.
If the 48° is from the lug wrench itself, that means that the force is 90° - 48° = 42° from the normal. So doing the calculation again (this time from where we started plugging in values) we get
U/cos(42) = F
117/0.743144825 = F
157.4390294 = F
Or 157 Newtons is required for this case.
Answer:
Approximately 
.
Explanation:
Let 
denote the gravitational constant. (
.)
Let 
and 
denote the mass of two objects separated by 
.
By Newton's Law of Universal Gravitation, the gravitational attraction between these two objects would measure:
.
In this question: 
is the mass of the moon, while 
is the mass of the water. The two are 
apart from one another.
Important: convert the unit of to standard units (meters, not kilometers) to reflect the unit of the gravitational constant .
.
.
