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nataly862011 [7]
1 year ago
15

In the sum of 4.34 + 5.66, the number of significant figures is

Physics
1 answer:
kifflom [539]1 year ago
4 0

Answer:

1

Explanation:

4.34 + 5.66 = 10

number of significant figures in 10: 1

(the significant figure here is 1)

here's a clear explanation from Northern Kentucky University (NKU)

[To determine the number of significant figures in a number use the following 3 rules:

Non-zero digits are always significant

Any zeros between two significant digits are significant

A final zero or trailing zeros in the decimal portion ONLY are significant

Example:  .500 or .632000 the zeros are significant

                .006  or .000968 the zeros are NOT significant ]

[For addition and subtraction use the following rules:

Count the number of significant figures in the decimal portion ONLY of each number in the problem

Add or subtract in the normal fashion

Your final answer may have no more significant figures to the right of the decimal than the LEAST number of significant figures in any number in the problem.]

(https://www.nku.edu/~intsci/sci110/worksheets/rules_for_significant_figures.html#:~:text=To%20determine%20the%20number%20of,decimal%20portion%20ONLY%20are%20significant)

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anyanavicka [17]

Answer:

1. E x 4πr² = ( Q x r³) / ( R³ x ε₀ )

Explanation:

According to the problem, Q is the charge on the non conducting sphere of radius R. Let ρ be the volume charge density of the non conducting sphere.

As shown in the figure, let r be the radius of the sphere inside the bigger non conducting sphere. Hence, the charge on the sphere of radius r is :

Q₁ = ∫ ρ dV

Here dV is the volume element of sphere of radius r.

Q₁ = ρ x 4π x ∫ r² dr

The limit of integration is from 0 to r as r is less than R.

Q₁ = (4π x ρ x r³ )/3

But volume charge density, ρ = \frac{3Q}{4\pi R^{3} }

So, Q_{1} = \frac{Qr^{3} }{R^{3} }

Applying Gauss law of electrostatics ;

∫ E ds = Q₁/ε₀

Here E is electric field inside the sphere and ds is surface element of sphere of radius r.

Substitute the value of Q₁ in the above equation. Hence,

E x 4πr² = ( Q x r³) / ( R³ x ε₀ )

7 0
3 years ago
A rigid tank contains nitrogen gas at 227 °C and 100 kPa gage. The gas is heated until the gage pressure reads 250 kPa. If the a
aleksley [76]

Answer:

 T₂ =602  °C

Explanation:

Given that

T₁ = 227°C =227+273 K

T₁ =500 k

Gauge pressure at condition 1 given = 100 KPa

The absolute pressure at condition 1 will be

P₁ = 100 + 100 KPa

P₁ =200 KPa

Gauge pressure at condition 2 given = 250 KPa

The absolute pressure at condition 2 will be

P₂ = 250 + 100 KPa

P₂ =350 KPa

The temperature at condition 2 = T₂

We know that

\dfrac{T_2}{T_1}=\dfrac{P_2}{P_1}\\T_2=T_1\times \dfrac{P_2}{P_1}\\T_2=500\times \dfrac{350}{200}\ K\\

T₂ = 875 K

T₂ =875- 273 °C

T₂ =602  °C

5 0
3 years ago
A force that is doing work on a ball when that ball is falling through the air.
Ronch [10]

Answer:

i think the answer is gravity

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2 years ago
Calculate the horizontal force that must be applied to a 1,300 kg vehicle to give it an acceleration of 2.6 m/s² on a level road
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The answer is 3,380 N
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2 years ago
Which quantum number gives the approximate energy of an electron in the quantum mechanical model of the atom? A) n B) I C) m1 D
alexdok [17]

Answer:

Option A) n

Explanation:

In accordance to Quantum Mechanical model of an atom:

  • The Principle Quantum number (n) gives the description of the shell of an electron and the energy level of an electron in an atom.
  • The angular momentum also referred to as Azimuthal Quantum number (l) gives the description of  the shape of the orbitals and helps in determination of angular momentum magnitude.
  • The magnetic quantum number (m_{1}) describes the energy levels or the number of orbitals contained in a subshell and the way these are oriented within.
  • The spin quantum no. (m_{2}) determines the elelctron spin's direction which may be (-\frac{1}{2}) or (+\frac{1}{2}).
4 0
2 years ago
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