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frutty [35]
3 years ago
7

How much work is required to move

Physics
1 answer:
Nikitich [7]3 years ago
6 0
The work is path independent since we have a conservative force.

Thus W=d\cdot\frac{q\cdot U}{d^2}=\frac{3.0\cdot9.0}{0.010}=\boxed{2700 J}

Answer (1)
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Please help my test is going on. Please answer both (i) and (ii). ​
Eduardwww [97]

Answer:

i. 7.5 m

ii. 15000 N

Explanation:

Area under vt graph shows the displacement

so area of triangle ABE= 1/2×15×2

=7.5 m

ii) F=ma

here, m=1000kg

and a=v-u/t

=15-0/1

a=15

F=1000×15=15000N

8 0
3 years ago
If the mass is displaced 0.270 m from equilibrium and released, what is its speed when it is 0.130 m from equilibrium?
puteri [66]

Answer:

The speed is 1.52 m.

Explanation:

Given that,

Displacement =0.270 m

Distance = 0.130 m

Suppose a 0.321-kg mass is attached to a spring with a force constant of 13.3 N/m.

We need to calculate the angular velocity

Using formula of angular velocity

\omega=\sqrt{\dfrac{k}{m}}

Put the value into the formula

\omega=\sqrt{\dfrac{13.3}{0.321}}

\omega=6.43\ rad/s

We need to calculate the velocity

Using formula of velocity

v=\omega\sqrt{A^2-x^2}

Put the value into the formula

v=6.43\times\sqrt{0.270^2-0.130^2}

v=1.52\ m/s

Hence, The speed is 1.52 m.

6 0
3 years ago
A type of wave is mechanical - what's the other type?
ANEK [815]

Answer:

There are three types of mechanical waves: transverse waves, longitudinal waves, and surface waves. :/

Explanation:

8 0
3 years ago
The effect of mechanical work on an object is _. (complete the sentence.)
Advocard [28]

Answer:

Displacement (i.e. change in its final position)

Explanation:

In classical mechanics work is described as the displacement of the body in the direction of the applied force.

<u>Mathematically given as:</u>

W=F.s\ cos\ \theta

where:

F = force on the body

s = displacement of the body

θ = angle between the force and direction of displacement

While force, acceleration, velocity can also be the answer for the blank space but the displacement effect is visible during and even after the work has been done, so one can notice the change in position of the object even when the person has not seen the process but just the initial condition of the body.

8 0
3 years ago
A horizontal spring with spring constant of 9.80 N/m is attached to a block with a mass of 1.20 kg that sits on a frictionless s
Andreas93 [3]

Answer:

Explanation:

Given

at certain point displacement and velocity is 0.345 m and 0.54 m/s

Therefore Potential and Kinetic Energy associated is

U=\frac{1}{2}kx^2

U=\frac{1}{2}\times 9.8\times (0.345)^2

U=0.583 J

Kinetic Energy K=\frac{1}{2}mv^2

k=\frac{1}{2}\times 1.2\times (0.54)^2=0.174 J

Total Energy T=U+K=0.583+0.174=0.757 J

Total Energy is conserved hence at maximum displacement  all energy will be Potential energy

T=\frac{1}{2}kA^2

where A=maximum displacement

0.757=\frac{1}{2}\times 9.8\times A^2

0.1544=A^2

A=0.393 m

Maximum speed occurs at equilibrium Position where Potential Energy is zero

thus T=\frac{1}{2}mv^2

0.757=\frac{1}{2}\times 1.2\times v_{max}^2

v_{max}=1.123 m/s

(c)When block is at 0.2 m from Equilibrium speed then its Potential Energy is

U=\frac{1}{2}kx^2=\frac{1}{2}\times 9.8\times (0.2)^2=0.196 J

T=U+K

K=0.757-0.196=0.561 J

K=\frac{1}{2}mv^2

0.561=\frac{1}{2}\times 1.2\times v^2

v=0.966 m/s

7 0
3 years ago
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