Calculate the percent ionization of nitrous acid in a solution that is 0.311 M in nitrous acid (HNO2) and 0.189 M in potassium n

Question

3 years ago

7

Calculate the percent ionization of nitrous acid in a solution that is 0.311 M in nitrous acid (HNO2) and 0.189 M in potassium n

itrite (KNO2). The acid dissociation constant of nitrous acid is
4.5 × 10^-4. Calculate the percent ionization of nitrous acid in a solution that is 0.311 M in nitrous acid (HNO2) and 0.189 M in potassium nitrite (KNO2). The acid dissociation constant of nitrous acid is
4.5 × 10^-4.

Chemistry

1 answer:

Alla [95] · Answer 1 · 2022-05-13T17:38:11+03:00

Alla [95]3 years ago

6 0

HNO2 =====> H+ + NO2-
Initial concentration = 0.311
C = -x,x,x 
E = 0.311-x,x,x

KNO2 ====>K+ + NO2-
Initial concentration = 0.189 
C= -0.189,0.189,0.189 
E = 0,0.189,0.189