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riadik2000 [5.3K]
3 years ago
11

Can someone help me thank you.

Mathematics
2 answers:
const2013 [10]3 years ago
6 0

Answer:

<h2><em><u>Area</u></em><em><u> </u></em><em><u>=</u></em><em><u> </u></em><em><u>117</u></em><em><u> </u></em><em><u>sq</u></em><em><u>.</u></em><em><u> </u></em><em><u>ft</u></em><em><u>.</u></em></h2><h2><em><u>Perimeter</u></em><em><u> </u></em><em><u>=</u></em><em><u> </u></em><em><u>44</u></em><em><u> </u></em><em><u>feet</u></em></h2>

Step-by-step explanation:

<em><u>Given</u></em><em><u>, </u></em>

Length of the bedroom = 13 feet

Width of the bedroom = 9 feet

<em><u>Therefore</u></em><em><u>, </u></em>

<em>First</em><em> </em><em>Case</em><em>:</em>

Area of the bedroom = Length × Width

= 13 feet × 9 feet

= 117 sq. ft.

<em>Second</em><em> </em><em>Case</em><em>:</em>

Perimeter of the bedroom = 2(Length + Width)

= 2 (13 + 9) feet

= 2 × 22 feet

= 44 feet

<em><u>Hence</u></em><em><u>,</u></em>

<em><u>Required</u></em><em><u> </u></em><em><u>area</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>bedroom</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>117</u></em><em><u> </u></em><em><u>sq</u></em><em><u>.</u></em><em><u> </u></em><em><u>ft</u></em><em><u>.</u></em><em><u> </u></em><em><u>and</u></em><em><u> </u></em><em><u>perimeter</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>bedroom</u></em><em><u> </u></em><em><u>os</u></em><em><u> </u></em><em><u>44</u></em><em><u> </u></em><em><u>feet</u></em><em><u> </u></em><em><u>(</u></em><em><u>Ans</u></em><em><u>)</u></em>

Molodets [167]3 years ago
3 0
To get the area, you do 13 * 9, which is 117, and the perimeter is 13+13+9+9 which is 44 :)
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Answer:

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