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marin [14]
3 years ago
5

Calculate the kinetic energy of a 0.145-kg baseball with a velocity of 80 mil/h. Express the answer in Joules.

Physics
1 answer:
Alexus [3.1K]3 years ago
5 0

Answer: 92.7Joules//

Explanation:

Kinetic energy of moving body is 1/2mv²

K=1/2mv²

Mass = 0.145kg

V=80mil/h = 80×1609.34/3600

=35.76m/s, since 1 mile = 1609.34m and 1 hour = 3600seconds.

From the equation K=1/2mv² you can input.

K=1/2×0.145×35.76²

K=1/2×185.422

K= 185.422/2

K=92.7J//

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The mass of an object with 500 J of kinetic energy moving with a velocity of 5 m/s is ______kg. (Report the answer to one signif
LUCKY_DIMON [66]
Kinetic energy is the energy that is associated with motion. It is the energy possessed by an object that is moving. It is calculated from one-half the product of the mass and the square of the velocity of the object. From this, we can calculate the mass of the object. We do as follows:

KE = mv^2/2
500 J = m(5 m/s)^2 / 2
m = 40 kg
8 0
3 years ago
Read 2 more answers
Two objects are placed 3 meters apart. If they were moved, at what distance would the NEW gravitational force be about 1/4 of th
gayaneshka [121]

Answer:

3/4

Explanation:

3 0
2 years ago
Is it proper to use an infinitely long cylinder model when finding the temperatures near the bottom or top surfaces of a cylinde
Gelneren [198K]

Answer:

No, it is not proper to use an infinitely long cylinder model when finding the temperatures near the bottom or top surfaces of a cylinder.

Explanation:

A cylinder is said to be infinitely long when is of a sufficient length. Also, when the diameter of the cylinder is relatively small compared to the length, it is called infinitely long cylinder.

Cylindrical rods can also be treated as infinitely long when dealing with heat transfers at locations far from the top or bottom surfaces. However, it not proper to treat the cylinder as being infinitely long when:

* When the diameter and length are comparable (i.e have the same measurement)

When finding the temperatures near the bottom or top of a cylinder, it is NOT PROPER TO USE AN INFINITELY LONG CYLINDER because heat transfer at those locations can be two-dimensional.

Therefore, the answer to the question is NO, since it is not proper to use an infinitely long cylinder when finding temperatures near the bottom or top of a cylinder.

8 0
2 years ago
Help me pleaseeee I will give you 42 points!<br> (I am dumb so that’s why)
Anit [1.1K]
Search each one of them up on GOOGLE it’s easier trust me
7 0
3 years ago
Read 2 more answers
Assume a rectangular strip of a material with an electron density of n=5.8x1020 cm-3. The strip is 8 mm wide and 0.8 mm thick an
vampirchik [111]

Answer: I = 111.69 pA

Explanation: The hall effect is all about the fact that when a semiconductor is placed perpendicularly to a magnetic field, a voltage is generated which could be measured at right angle to the current path. This voltage is known as the hall voltage.

The hall voltage of a semiconductor sensor is given below as

V = I×B/qnd

Where V = hall voltage = 1.5mV =1.5/1000=0.0015V

I = current =?,

n= concentration of charge (electron density) = 5.8×10^20cm^-3 = 5.8×10^20/(100)³ = 5.8×10^14 m^-3

q = magnitude of an electronic charge=1.609×10^-19c

B = strength of magnetic field = 5T

d = thickness of sensor = 0.8mm = 0.0008m

By slotting in the parameters, we have that

0.0015 = I × 5/5.8×10^14 × 1.609×10^-19×0.0008

0.0015 = I×5/7.446×10^-8

I = (0.0015 × 7.446×10^-8)/5

I = 111.69*10^(-12)

I = 111.69 pA

3 0
3 years ago
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