Answer:
I think it's dio to atmospheric pressure.
Answer:
2.40 x 10⁻¹³ C
Explanation:
= number of electrons = 6.25 x 10⁶
= charge on electron = - 1.6 x 10⁻¹⁹ C
= number of protons = 7.75 x 10⁶
= charge on proton = 1.6 x 10⁻¹⁹ C
Net charge is given as
Q = +
Q = (- 1.6 x 10⁻¹⁹) (6.25 x 10⁶) + (1.6 x 10⁻¹⁹) (7.75 x 10⁶)
Q = 2.40 x 10⁻¹³ C
Voltage is necessary for charge to flow
<span>Frequency is calculated by dividing the speed of light by the wavelength. Using the normal constant of 3x10^8 m/s divided by 530 nm you can calculate it. You need to convert nm to m so it is 5.3x10^-7. Divide the constant of light by that and you get 5.66 x10^14 hz, where hz is the function 1/s.</span>
is the best estimate of the density of the air on the planet.
Given:
The mass of the conical flask with stopper is 457.23 grams and the volume is .
Mass of conical flask and a stopper after removing the air is 456.43 g
To find:
The density of the air on the planet.
Solution;
Mass of the conical flask and stopper with air on the planet= 457.23 g
Mass of conical flask with a stopper and without air on the planet = 456.43 g
Mass of the air in the conical flask on the planet =m
The volume of the conical flask =
The volume of the air in the conical flask =
The density of the air on the planet = d
is the best estimate of the density of the air on the planet.
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