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2 years ago

Help whoever answers all gets marked brainliest

Chemistry

2 answers:

Lelechka [254]2 years ago

6 0

See H and C have shared their electrons so it's Covalent bonding

Yes here we can see the dots and crosses clearly.

Dot and crosses digram

It's Methane or CH_4

4 single bonds

There is no double bond

Mkey [24]2 years ago

5 0

Answer:

See H and C have shared their electrons so its Covalent bonding

Yes, here we can see the dots and crosses clearly.

Dot and crosses diagram

It's Methane or CH_4

4 single bonds

There is no double bond

Explanation:

mark the person that did it before me brainliest

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3 years ago

If 20.0 g of NaOH is added to 0.750 L of 1.00 M Cd(NO₃)₂, how many grams of Cd(OH)₂ will be formed in the following precipitatio

bulgar [2K]

Answer:

$m_{Cd(OH)_2}=36.6 gCd(OH)_2$

Explanation:

Hello.

In this case, for the given chemical reaction, in order to compute the grams of cadmium hydroxide that would be yielded, we must first identify the limiting reactant by computing the yielded moles of that same product, by 20.0 grams of NaOH (molar mass = 40 g/mol) and by 0.750 L of the 1.00-M solution of cadmium nitrate as shown below considering the 1:2:1 mole ratios respectively:

$n_{Cd(OH)_2}^{by\ NaOH}=20.0gNaOH*\frac{1molNaOH}{40gNaOH} *\frac{1molCd(OH)_2}{2molNaOH} =0.25molCd(OH)_2\\\\n_{Cd(OH)_2}^{by\ Cd(NO_3)_2}=0.750L*1.00\frac{molCd(NO_3)_2}{L}*\frac{1molCd(OH)_2}{1molCd(NO_3)_2} =0.75molCd(OH)_2$

Thus, since 20.0 grams of NaOH yielded less of moles of cadmium hydroxide, NaOH is the limiting reactant, therefore the mass of cadmium hydroxide (molar mass = 146.4 g/mol) is:

$m_{Cd(OH)_2}=0.25molCd(OH)_2*\frac{146.4gCd(OH)_2}{1molCd(OH)_2} \\\\m_{Cd(OH)_2}=36.6 gCd(OH)_2$

Best regards.

4 0

3 years ago

Need help answering this question

a_sh-v [17]

Answer:

1st = saturated

Explanation:

Bro first ka answer saturated he

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1 year ago