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2 years ago

Copper(Ii) Iodate + Potassium Carbonate = Potassium Iodate + copper(I)carbonate into a formula equation ?

Chemistry

1 answer:

barxatty [35]2 years ago

7 0

Answer:

Cu(IO3)2 + K2CO3 → 2KIO3 + CuCO3

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What is #6 ,7,8 need help

weeeeeb [17]

#6 should be the independent variable because that's the one you can control

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3 years ago

A certain liquid sample has a volume of 14.7 mL and a mass of 22.8 grams. Calculate the density.

ira [324]

M = 22.8 g
V = 14.7 mL
ρ - ?

ρ = m/V
ρ = 22.8/14.7 = 1.55 g/mL

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3 years ago

¿Cuál era su juego favorito cuando eran niños?

blagie [28]

Answer:

mi juego favorito probablemente sería Mine craft cuando era más joven, aunque sigue siendo uno de mis juegos favoritos

Explanation:

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3 years ago

Predict, using Boyle’s Law, what will happen to a balloon that an ocean diver takes to a pressure of 202 kPa (normal atmospheric

kaheart [24]

Explanation:

Balloon that an ocean diver takes to a pressure of 202 k Pa will get reduced in size that is the volume of the balloon will get reduced. This is because pressure and volume of the gas are inversely related to each other.

According to Boyle's law: The pressure of the gas is inversely proportional to the volume occupied by the gas at constant temperature(in Kelvins).

$pressure\propto \frac{1}{volume}$ (At constant temperature)

The pressure beneath the sea is 202 kPa and the atmospheric pressure is 101.3 kPa . This increase in pressure will result in decrease in volume occupied by the gas inside the balloon with decrease in size of a balloon. Hence, the size of the balloon will get reduced at 202 kPa (under sea).

7 0

2 years ago

In a certain electrolysis experiment, 1.24 g of Ag were deposited in one cell (containing an aqueous AgNO3 solution), while 0.65

eduard

Answer:

The correct answer is 169.56 g/mol.

Explanation:

Based on the given information, the mass of Ag deposited is 1.24 g, and the mass of unknown metal X deposited in another cell is 0.650 g. The number of moles of electrons can be determined as,

= 1.24 g Ag * 1mol Ag/107.87 g/mol Ag * 1 mol electron/1 mol Ag ( the molecular mass of Ag is 107.87 g/mol)

= 0.0115 mole of electron

The half cell reaction for the metal X is,

X^3+ (aq) + 3e- = X (s)

From the reaction, it came out that 3 faraday will reduce one mole of X^3+.

The molar mass of X will be,

= 0.650 g/0.0115 *3 mol electron/1 mol

= 56.52 * 3

= 169.56 g/mol

7 0

3 years ago