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3 years ago

What happened to gas produces by the tablet when it reaches the top of the bottle?

Chemistry

1 answer:

Tomtit [17]3 years ago

5 0

Answer:

it sank to the bottom and started dissolving and creating a gas (gas production is a sign that a chemical change is happening)!

Explanation:

As the gas bubbles rose, they carried some of the colored water with them. When the blob of water reached the top, the gas escaped and down went the water.

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Please solve this problem using dimensional analysis. Show your

Citrus2011 [14]

<h3>Answer:</h3>

4.3 miles

<h3>Explanation:</h3>

We are given;

Distance of 22,704 feet

We are required to determine the number of miles in 22,704 feet

To convert one unit to another we use conversion factors
Therefore, we need to know the suitable conversion factor.
That is, 1 mile/5,280 feet
Thus, to determine the number of miles we multiply the number of feet with the conversion factor.

That is;

= 22,704 feet × 1 mile/5,280 feet

= 4.3 miles

Therefore, there are 4.3 miles in 22,704 feet

5 0

3 years ago

What type of bonding holds the atoms in an h2o molecule together?

Ivanshal [37]

Covalent bond two non metals

3 0

3 years ago

Give examples which indicate that nylon fibres are very strong.

Readme [11.4K]

Explanation:

is used for making ropes, used for climbing rocks and for making parachutes. Their usage shows that nylon fibres have high tensile strength

3 0

3 years ago

You want to know how many moles of gas your lungs can hold. You start off with a balloon that has 1.4 moles of gas and occupies

Mrrafil [7]

Number of moles : n₂ = 1.775 moles

<h3>Further explanation</h3>

Given

Moles = n₁ = 1.4

Volume = V₁=22.4 L

V₂=28.4 L

Required

Moles-n₂

Solution

Avogadro's hypothesis, at the same temperature and pressure, the ratio of gas volume will be equal to the ratio of gas moles

The ratio of gas volume will be equal to the ratio of gas moles

$\tt \dfrac{V_1}{V_2}=\dfrac{n_1}{n_2}$

Input the values :

n₂ = (V₂ x n₁)/V₁

n₂ = (28.4 x 1.4)/22.4

n₂ = 1.775 moles

4 0

3 years ago

112 g of aluminum carbide react with 174 g water to produce methane and aluminum hydroxide in the reaction shown below.

dolphi86 [110]

<u>Answer:</u> 4.999 moles of excess reactant will be left over.

<u>Explanation:</u>

Limiting reagent is defined as the reagent which is completely consumed in the reaction and limits the formation of the product.

Excess reagent is defined as the reagent which is left behind after the completion of the reaction.

The number of moles is defined as the ratio of the mass of a substance to its molar mass.

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ .....(1)

Given mass of aluminium carbide = 112 g

Molar mass of aluminium carbide = 143.96 g/mol

Putting values in equation 1:

$\text{Moles of aluminium carbide}=\frac{112g}{143.96g/mol}=0.778mol$

For the given chemical reaction:

$2Al_4C_3(s)+12H_2O(l)\rightarrow 3CH_4(g)+4Al(OH)_3(s)$

By the stoichiometry of the reaction:

2 moles of aluminium carbide reacts with 12 moles of water

So, 0.778 moles of aluminium carbide will react with = $\frac{12}{2}\times 0.778=4.668 mol$ of water

Given mass of water = 174 g

Molar mass of water = 18 g/mol

Putting values in equation 1:

$\text{Moles of water}=\frac{174g}{18g/mol}=9.667mol$

Moles of excess reactant (water) left = 9.667 - 4.668 = 4.999 moles

Hence, 4.999 moles of excess reactant will be left over.

8 0

3 years ago