Answer:
6.68 X 10^-11
Explanation:
From the second Ka, you can calculate pKa = -log (Ka2) = 6.187
The pH at the second equivalence point (8.181) will be the average of pKa2 and pKa3. So,
8.181 = (6.187 + pKa3) / 2
Solving gives pKa3 = 10.175, and Ka3 = 10^-pKa3 = 6.68 X 10^-11
The complete and <span>balanced equation for this single-displacement reaction would be written as follows:
</span><span>Li+NaOH--> LiOH + Na
In this reaction, lithium replace sodium in the compound sodium hydroxide forming lithium hydroxide and sodium metal as products. Hope this answers the question.</span>
1. B
2. C
3. E
4. D
5. A
6. B
7. A
8. E
9. A
Hope this helps!
H• •Be• •H --> H:Be:H
Since there are 4 valence electrons in total, Beryllium has 2 and Hydrogen has 2. You would put the Be in the middle because there is only 1 of them.
