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Vinvika [58]
2 years ago
6

Hey Friends Can Yall Help Me Show Ya Work And Don’t Comment No B.S Cause Yu Will Get Cursed Out

Chemistry
1 answer:
melisa1 [442]2 years ago
3 0
C. Speed is how fast, velocity has direction and acceleration is a change in velocity.
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Seawater is typically 3.5% salt and has a density of 1.03 g/mL. How many grams of salt would be needed to prepare enough seawate
Bas_tet [7]

Answer:

Amount of salt needed is around 2.3*10³ g

Explanation:

The salt content in sea water = 3.5 %

This implies that there is 3.5 g salt in 100 g sea water

Density of seawater = 1.03 g/ml

Volume of seawater = volume of tank = 62.5 L = 62500 ml

Therefore, the amount of seawater required is:

=Density*Volume = 1.03g/ml*62500ml = 6.44*10^{4} g

The amount of salt needed for the calculated amount of seawater is:

=\frac{6.44*10^{4}g\ water*3.5g\ salt }{100g\ water} =2254 g =2.3*10^{3} g

8 0
3 years ago
The standard length of a certain golf club is 116.84 cm. You measure the club to be 116.85 cm long. You measure it again and fin
IgorC [24]

Answer:

The first measurement is 116.84 cm, and the second measurement is 116.85 cm.

Explanation:

The problem provides both the first and second measurements so all you have to do is fill in the blank with them.

8 0
3 years ago
Given these reactions, X ( s ) + 1 2 O 2 ( g ) ⟶ XO ( s ) Δ H = − 668.5 k J / m o l XCO 3 ( s ) ⟶ XO ( s ) + CO 2 ( g ) Δ H = +
qwelly [4]

<u>Answer:</u> The \Delta H^o_{rxn} for the reaction is -1052.8 kJ.

<u>Explanation:</u>

Hess’s law of constant heat summation states that the amount of heat absorbed or evolved in a given chemical equation remains the same whether the process occurs in one step or several steps.

According to this law, the chemical equation is treated as ordinary algebraic expressions and can be added or subtracted to yield the required equation. This means that the enthalpy change of the overall reaction is equal to the sum of the enthalpy changes of the intermediate reactions.

The given chemical reaction follows:

X(s)+\frac{1}{2}O_2(g)+CO_2(g)\rightarrow XCO_3(s)      \Delta H^o_{rxn}=?

The intermediate balanced chemical reaction are:

(1) X(s)+\frac{1}{2}O_2(g)\rightarrow XO(s)    \Delta H_1=-668.5kJ

(2) XCO_3(s)\rightarrow XO(s)+CO_2     \Delta H_2=+384.3kJ

The expression for enthalpy of the reaction follows:

\Delta H^o_{rxn}=[1\times \Delta H_1]+[1\times (-\Delta H_2)]

Putting values in above equation, we get:

\Delta H^o_{rxn}=[(1\times (-668.5))+(1\times (-384.3))=-1052.8kJ

Hence, the \Delta H^o_{rxn} for the reaction is -1052.8 kJ.

7 0
3 years ago
Which type of precipitation occurs when the water vapor in a cloud freezes to form ice crystals?
Verizon [17]

Answer:snow i think

Explanation:

6 0
3 years ago
Read 2 more answers
Someone please help me with this ???
Verizon [17]

Answer:

c

Explanation:

6 0
2 years ago
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