Solution :
cs=zeros(9001);
ca=zeros(9001);
cp=zeros(9001);
psi=zeros(9001);
t=[0:0.1:900];
cs(1)=0.5;
ce(1)=0.001;
cp(1)=0;
ca(1)=0;
psi(1)=0;
for i=1:1:9000
cs(i+1)=cs(i)-0.1*((0.015*cs(i))/(5.53+cs(i)));
cp(i+1)=cp(i)+0.1*((0.015*cs(i))/(5.53+cs(i))-0.0026*cp(i));
ca(i+1)=ca(i)+0.1*0.0026*cp(i);
psi(i+1)=((cp(i+1)-cp(i)))/((cs(i)-cs(i+1)));
end
plot(t,cs,t,cp,t,ca);
plot(t,psi);
Answer: i think the answer is D) tendency for REM sleep to increase following REM sleep deprivation.
Explanation:REM rebound is the lengthening and increasing frequency and depth of rapid eye movement (REM) sleep which occurs after periods of sleep deprivation.
Answer:
See image attached.
Explanation:
This device features priority encoding of the inputs
to ensure that only the highest order data line is en-
coded. Nine input lines are encoded to a four line
BCD output. The implied decimal zero condition re-
quires no input condition as zero is encoded when
all nine datalinesare athigh logic level. Alldata input
and outputs are active at the low logic level. All in-
puts are equipped with protection circuits against
static discharge and transient excess voltage.
Explanation:
Engineering is science in practical terms. It is the application of scientific findings in problem solving and creating a better world.
How does technological advancements create more problems for engineers?
- Loss of job to automation: the world is driving at automating work processes through the use of specially designed and crafted machinery. Work is now properly being done using machines with little to no human input in the whole process. This is a huge let off for engineers. Engineers have to compete with machines which are their own inventions for jobs now.
- Fast paced work environment: machines can handle work more efficiently and faster than the people making them. There is an increasing race between engineers and their own inventions today for better product delivery. Unless a machine is faulty, they are more productive and efficient than man. This can cause engineers to want to catch up with their own inventions leading to a work life of stress.
- Environmental problems they cannot solve: most inventions use components from the environment. They release effluents that are very difficult to be properly disposed or stored. This is a huge problem for engineers and can lead to ethical calls from the government and the populace. In short, they can create problems they are expected to solve but cannot solve.
- Social problems: engineers can be portrayed as terrible beings for their own inventions. This leads to psychological problems on a good and creative invention. For example, rare earth metals in DR Congo are instrumental in making solar panels, but mining of these metals have forced several thousands of people into hard and intense labor on mines; there is a call on technological firms to stop exploiting people this way for their own gains.
- Misuse of technology: any good technology can be put into the wrong use. A nuclear reaction can be packaged into a bomb and also, it can be the center of electricity generation on a commercial scale. How can engineers solve this kind of problem? Technological inventions are subjective in their usage.
Learn more:
New technology brainly.com/question/5768621
#learnwithBrainly
Answer:
(a) E = 0 N/C
(b) E = 0 N/C
(c) E = 7.78 x10^5 N/C
Explanation:
We are given a hollow sphere with following parameters:
Q = total charge on its surface = 23.6 μC = 23.6 x 10^-6 C
R = radius of sphere = 26.1 cm = 0.261 m
Permittivity of free space = ε0 = 8.85419 X 10−12 C²/Nm²
The formula for the electric field intensity is:
E = (1/4πεo)(Q/r²)
where, r = the distance from center of sphere where the intensity is to be found.
(a)
At the center of the sphere r = 0. Also, there is no charge inside the sphere to produce an electric field. Thus the electric field at center is zero.
<u>E = 0 N/C</u>
(b)
Since, the distance R/2 from center lies inside the sphere. Therefore, the intensity at that point will be zero, due to absence of charge inside the sphere (q = 0 C).
<u>E = 0 N/C</u>
(c)
Since, the distance of 52.2 cm is outside the circle. So, now we use the formula to calculate the Electric Field:
E = (1/4πεo)[(23.6 x 10^-6 C)/(0.522m)²]
<u>E = 7.78 x10^5 N/C</u>
