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sveta [45]
3 years ago
7

THE COMPUND INTEREST ON RS 30,000AT 7% PER ANNUM IS RS 4347 THE PERIOD IN YEARS

Engineering
2 answers:
Georgia [21]3 years ago
6 0

Answer:

2 years

1st year ci 2100

2nd year ci 2100 +147(7%of 2100)

timofeeve [1]3 years ago
4 0

Answer:

what wym

Explanation:

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A ____ is marked by two sets of double yellow lines, with each set having a broken line on the inside, and a solid line on the o
Vitek1552 [10]

Answer:

  center left-turn lane

Explanation:

A <em>center left turn lane</em> will be marked as described. The arrows, if present, generally indicate that left turns are permitted from the lane with these markings.

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If the double yellow lines are solid, they are considered to be a "barrier" and are not to be crossed.

7 0
3 years ago
Read 2 more answers
Which of following are coding languages used in controlling a robot? *
Bess [88]

Answer:

C/C++

Explanation:

C/C++

7 0
2 years ago
Tires can be recycled instead of thrown out.<br> True<br> False
Arisa [49]

Answer:

True :)

Explanation:

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Hope it helped have a nice day! :)

8 0
2 years ago
A well insulated turbine operates at steady state. Steam enters the turbine at 4 MPa with a specific enthalpy of 3015.4 kJ/kg an
Anarel [89]

Answer:

power developed by the turbine = 6927.415 kW

Explanation:

given data

pressure = 4 MPa

specific enthalpy h1 = 3015.4 kJ/kg

velocity v1 = 10 m/s

pressure = 0.07 MPa

specific enthalpy h2 = 2431.7 kJ/kg

velocity v2 = 90 m/s

mass flow rate = 11.95 kg/s

solution

we apply here  thermodynamic equation that

energy equation that is

h1 + \frac{v1}{2}  + q = h2 + \frac{v2}{2}  + w

put here value with

turbine is insulated so q = 0

so here

3015.4 *1000 + \frac{10^2}{2}  =  2431.7 * 1000 + \frac{90^2}{2}  + w

solve we get

w = 579700 J/kg = 579.7 kJ/kg

and

W = mass flow rate × w

W = 11.95 × 579.7

W = 6927.415 kW

power developed by the turbine = 6927.415 kW

7 0
3 years ago
If the bending moment (M) is 4,176 ft-lb and the beam is an 1 beam, calculate the bending stress (psi) developed at a point with
SpyIntel [72]

Answer:

Bending stress at point 3.96 is \sigma_b = 1.37 psi

Explanation:

Given data:

Bending Moment M is 4.176 ft-lb = 50.12 in- lb

moment of inertia I = 144 inc^4

y = 3.96 in

\sigma_b = \frac{M}{I} \times y

putting all value to get bending stress

\sigma_b = \frac{50.112}{144} \times 3.96  

\sigma_b =  1.37 psi

Bending stress at point 3.96 is \sigma_b = 1.37 psi

3 0
3 years ago
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