89.1% Au
The molar mass of Au2O3 is 2(196.97) + 3(16.00) = 441.94 g/mol
The mass percent of Au is therefore 2(196.97) / 441.94, which is 393.94/441.94 = 0.891 —> 89.1%
Dry and desert conditions
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Answer:
Atoms=9.033*10^23 atoms
Explanation:
Atoms=no.of miles*Avogadro's no.
Atoms=1.5*6.022*10^23
Atoms=9.033*10^23 atoms
Heat flows from a region of greater potential to lower potential?