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ad-work [718]
3 years ago
7

The element manganese is represented by the symbol ____. (Capitalization is important.)

Chemistry
2 answers:
lesya [120]3 years ago
7 0
The chemical symbol for manganese is Mn.
Elis [28]3 years ago
4 0
The answer is Mn. (Capital M lowercase n)
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konstantin123 [22]

Answer:

the temperature of the star

Explanation:

The color of stars usually indicates the temperature of the star.

A star that is relatively cold usually shows a typical red color.

The hottest stars have a blue color.  

  • These star colors have been used by astronomers to determine their temperature.
  • A broad spectrum between blue, the hottest color,  and red the coldest is used.
  • Class O stars are usually the blue colored ones
  • Class M is the coldest with red color

8 0
3 years ago
Is the narrator male or female in the story leaving?​
AlladinOne [14]
The narrator is a female

Hope this helps
8 0
3 years ago
Which of these is a characteristic of science?
Ivahew [28]

D. It gives the same results when experiments are repeated

3 0
3 years ago
Read 2 more answers
If the freezing point of the solution had been incorrectly read 0.3 °C lower than the true freezing point, would the calculated
Dovator [93]

Answer : The molar mass of the solute would be low.

Explanation :

Formula used for depression in freezing point is:  

\Delta T_f=i\times K_f\times m\\\\T^o-T_s=i\times K_f\times\frac{w_b}{M_b}\times w_a}

where,

\Delta T_f = change in freezing point

\Delta T_s = freezing point of solution

\Delta T^o = freezing point of water

i = Van't Hoff factor

K_f = freezing point constant

m = molality

w_b = mass of solute

w_a = mass of solvent

M_b = molar mass of solute

From the formula we conclude that, when the freezing point of the solution read incorrectly that is freezing point of the solution is lower than the true freezing point then this means that change in freezing point would be high and the molar mass of the solute would be low.

Hence, the molar mass of the solute would be low.

6 0
3 years ago
How would you prepare 100 ml of 0.4 M MgSO4 from a stock solution of 2 M MgSO4?
miss Akunina [59]
OK, so to answer this question, you will simply use the molality equation which is as follows:
<span>M1V1 = M2V2 
In the givens you have:
M1 = 2M
V1 is the unknown
M2 = 0.4M
V2 = 100 ml

</span>plug in the givens in the above equation:
<span>2 x V1 = 0.4 x 100 
</span>therefore:
V1 = 20 ml

Based on this: you should take 20 ml of the 2 M solution and make volume exactly 100 ml in a volumetric flask by diluting in water.

7 0
3 years ago
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