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3 years ago

Which of the following organs are found in the

Physics

1 answer:

Hatshy [7]3 years ago

3 0

Answer:

small intestine, tongue and large intestine

Explanation:

The GI tract is a series of hollow organs joined in a long, twisting tube from the mouth to the anus. The hollow organs that make up the GI tract are the mouth, esophagus, stomach, small intestine, large intestine, and anus. The liver, pancreas, and gallbladder are the solid organs of the digestive system.

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What is the cell emf for the concentrations given? Express your answer using two significant figures.

alisha [4.7K]

Complete Question

A voltaic cell is constructed with two $Zn^{2+}$ $- Zn$ electrodes. The two cell compartment have $[Zn^{2+}] = 1.6 \ M$ and $[Zn^{2+}] = 2.00*10^{-2} \ M$ respectively.

What is the cell emf for the concentrations given? Express your answer using two significant figures

Answer:

The value is $E = 0.06 V$

Explanation:

Generally from the question we are told that

The concentration of $[Zn^{2+}]$ at the cathode is $[Zn^{2+}]_a = 1.6 \ M$

The concentration of $[Zn^{2+}]$ at the anode is $[Zn^{2+}]_c = 2.00*10^{-2} \ M$

Generally the the cell emf for the concentration is mathematically represented as

$E = E^o - \frac{0.0591}{2} log\frac{[Zn^{2+}]a}{ [Zn^{2+}]c}$

Generally the $E^o$ is the standard emf of a cell, the value is 0 V

$E = 0 - \frac{0.0591}{2} * log[\frac{ 2.00*10^{-2}}{1.6} ]$

=> $E = 0.06 V$

4 0

3 years ago

Which two technologies use the same range of radio wave frequencies? television broadcasting and AM radio broadcasting cell phon

Tju [1.3M]

Let us reject some answers. AM and FM radio waves do not interfere. Am are an orders of magnitude larger than FM waves. FM waves belong to microwaves, a subcategory of radiowaves while AM does not. Similarly, AM and TV have not the same, because TV uses a subset of the frequencies used in FM. The correct answe is that CB radios and submarine communication happen at the same wavelengths/frequencies, namely low frequency radiowaves.

4 0

4 years ago

Read 2 more answers

The red giant Betelgeuse has a surface temperature of 3000 K and is 600 times the diameter of our sun. (If our sun were that lar

Nat2105 [25]

Answer:

Explanation:

a )

Radius of the sun = .69645 x 10⁹ m .

600 times = 600 x .69645 x 10⁹ m

= 4.1787 x 10¹¹ m .

surface area A = 4π (4.1787 x 10¹¹)²

= 219.317 x 10²²

energy radiated E = σ A Τ⁴

= 5.67 x 10⁻⁸ x 219.317 x 10²² x (3000)⁴

= 100695 x 10²⁶ J

To know the wavelength of photon emitted

$\lambda_mT= b$

$\lambda_m= \frac{b}{T}$

= 2.89777 x 10⁻³ / 3000

= 966 nm

= 1275 /966 eV

1.32 x 1.6 x 10⁻¹⁹ J

= 2.112 x 10⁻¹⁹ J

No of photons radiated = 100695 x 10²⁶ / 2.112 x 10⁻¹⁹

= 47677.5 x 10⁴⁵

= .476 x 10⁵⁰ .

b )

energy radiated by our sun per second

E₂ = σ A 5800⁴

energy radiated by Betelgeuse per second

E₁ = σ x 600²A x 3000⁴

E₁ / E₂ = σ x 600²A x 3000⁴ / σ A 5800⁴

= 36 X 10⁴ x 3⁴ x 10¹² / 58⁴ x 10⁸

= 25.76 x 10⁸ x 10⁻⁵

= 25760 times .

4 0

3 years ago

A balloon holds 5.00 mol of a mono-atomic gas at a temperature of 5.00oC and at a pressure of 1.20 atm. The gas isothermally abs

Nadya [2.5K]

The answer is b try it out man theusgavqhhw

7 0

3 years ago

What does the Q stand for in the enthalpy of fusion equation?

pychu [463]

The Q in the enthalpy of fusion equation stands for heat energy absorbed or released.

<h3>What is enthalpy?</h3>

In thermodynamics, enthalpy is a measure of the heat content of a chemical or physical system.

The enthalpy of fusion is the amount of heat energy required to convert a unit mass of a solid at its melting point into a liquid without an increase in temperature.

Its units are usually Joules per gram (J/g) or calories per gram (cal/g).

The enthalpy of fusion equation is given as follows:

Q = m·ΔHf

Where;

Q = heat energy
m = mass
ΔHf = heat of fusion

Therefore, the Q in the enthalpy of fusion equation stands for heat energy absorbed or released.

Learn more about enthalpy of fusion at: brainly.com/question/20897184

#SPJ1

3 0

2 years ago