Question

A horizontal rectangular surface has dimensions 3.20 cm by 3.90 cm and is in a uniform magnetic field that is directed at an angle of 32.0 ∘ above the horizontal.Part AWhat must the magnitude of the magnetic field be to produce a flux of 3.80 ×10−4 Wb through the surface?Express your answer with the appropriate units.

Answer 1

Answer:

$B =0.574\ T$  

Explanation:

given,

dimension of rectangular surface = 3.20 cm x 3.90 cm

angle of magnetic field above horizontal = 32°

θ = 90° - 32° = 58°

flux = Ф = 3.80 ×10⁻⁴ Wb

Magnetic filed = ?

$\phi=\int B.ds$

$\phi= B.ds cos \theta$

$B =\dfrac{\phi}{ds cos \theta}$

$B =\dfrac{3.8 \times 10^{-4}}{3.20 \times 3.9 \times 10^{-4}cos 58^0}$

$B =0.574\ T$  

The magnetic field produced is equal to $B =0.574\ T$