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Oksanka [162]
2 years ago
11

The most likely van't Hoff factor for an 0.01 m calcium iodide solution is

Chemistry
1 answer:
monitta2 years ago
5 0

This problem is providing us with the molality of a solution of calcium iodide as 0.01 m. So the most likely van't Hoff factor is required and theoretically found to be 3 due to the following:

<h3>Van't Hoff factor:</h3>

In chemistry, the correct characterization of solutions also imply the identification of the ions it will release in aqueous solution. For that reason, the van't Hoff factor gives us an idea of this number, according to the formula the solute has got.

In such a way, for calcium iodide, we write its ionization equation as shown below:

CaI_2\rightarrow Ca^{2+}+2I^-

Assuming it is able to ionize due to the low molality, because if it was higher, then it won't ionize. Hence, since we have three moles of ion products, one Ca²⁺ and two I⁻, we can conclude the van't Hoff factor would be 3, although calculations may lead to a different, yet close result.

Learn more about the van't Hoff factor: brainly.com/question/23764376

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Lubov Fominskaja [6]
In an acidic solution, the concentration of H+ is greater than the concentration of OH-. The pH will be less than 7.
In a basic solution, the concentration of OH- is greater than the concentration of H+. The pH will be greater than 7.
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5 0
3 years ago
Determine the poh of a 0.348 m ba(oh)2 solution at 25°c.
vladimir1956 [14]

<u>Given:</u>

Concentration of Ba(OH)2 = 0.348 M

<u>To determine:</u>

pOH of the above solution

<u>Explanation:</u>

Based on the stoichiometry-

1 mole of Ba(OH)2 is composed of 1 mole of Ba2+ ion and 2 moles of OH- ion

Therefore, concentration of OH- ion = 2*0.348 = 0.696 M

pOH = -log[OH-] = - log[0.696] = 0.157

Ans: pOH of 0.348M Ba(OH)2 is 0.157

6 0
3 years ago
Read 2 more answers
If a gas in a box with fixed volume has a pressure of 913 torr at 15 C, what temperature should the gas be heated to double the
algol13
<span>700 mL hop it helps u ok</span>
4 0
3 years ago
1.15.7 cm3 of HCl completely neutralised 25 cm3 of LiOH. The HCl was 2 mol/dm3.The equation is :
Whitepunk [10]

Answer:

C₂ = 1.26 mol/dm³

Explanation:

Given data:

Volume of HCl =V₁ =  15.7 cm³

Volume of LiOH = V₂ =  25 cm³

Concentration of HCl =C₁ = 2 mol/dm³

Concentration of LiOH =C₂=  ?

Solution:

Chemical equation:

LiOH + HCl    →     LiCl + H₂O

Formula:

C₁V₁   = C₂V₂

by putting values,

15.7 cm₃× 2 mol/dm³ = C₂× 25 cm³

C₂ = 15.7 cm₃× 2 mol/dm³ / 25 cm³

C₂ = 31.4 cm₃.mol/dm³ / 25 cm³

C₂ = 1.26 mol/dm³

8 0
2 years ago
Which chemical equation correctly represents the reaction that takes place when nitrogen gas and hydrogen gas are formed as ammo
Leviafan [203]

Answer:

  • d. 2NH3(g)-N2(g)+3H2(g)
4 0
2 years ago
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