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Anna [14]
3 years ago
5

A 10 V battery is connected to a voltage divider circuit

Physics
1 answer:
Svetradugi [14.3K]3 years ago
5 0

Answer:

a) C. 7.5 V

b) A. 2.5 V

Explanation:

First, we find the total resistance of the circuit. A voltage divider circuit is a series circuit. Therefore, its total resistance will be the sum of individual resistances:

R = R_{1}+R_{2}\\R = 100\ \Omega + 300\ \Omega\\R = 400\ \Omega\\

a)

Now, we will apply the voltage divider rule on this circuit to find the voltage across the 300 Ω Resistor (R₂):

V_{2} = R_{2}\frac{V}{R}\\\\V_{2} = (300\ \Omega)\frac{10\ V}{400\ \Omega}\\\\

V₂ = 7.5 V

Therefore, the correct option is:

<u>C. 7.5 V</u>

<u></u>

b)

Now, the voltage across the 100 Ω Resistor (R₁) will be:

V = V_{1}+V_{2}\\V_{1} = V-V_{2}\\V_{1} = 10\ V - 7.5\ V\\V_{1}=2.5\ V

Therefore,the correct option is:

<u>A. 2.5 V</u>

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Riders in an amusement park ride shaped like a Viking ship hung from a large pivot are rotated back and forth like a rigid pendu
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Answer:

a)  v = 16.57 m / s, b)  a = 19.6 m / s², d)    N = 1.76 10³ N,     N / W = 3

Explanation:

This exercise looks interesting, but I think you have some problem with the writing, the questions seem a bit disconnected from the initial text.

Let's answer the questions.

a) For this part we can use energy considerations.

Starting point. The upper part of the trajectory indicates that the arm is horizontally

          Em₀ = U = m g h

in this case h = r

Final point. For lower of the trajectory

          Em_f = K = ½ m v²

as they indicate that there is no friction

         Em₀ = em_f

         mgh = ½ m v²

         v = \sqrt{2gh}

let's calculate

        v = \sqrt{2 \ 9.8 \ 14.0}

         v = 16.57 m / s

b) the centripetal acceleration has the formula

           a = v² / r

           a = 16.57² / 14.0

           a = 19.6 m / s²

c) see attached where the diagram is

where N is the normal and w the weight

d) let's use Newton's second law

               N-W = m a

               N - mg = m ar

               N = m (g + a)

let's calculate

               N = 60.0 (9.8 + 19.6)

               N = 1.76 10³ N

the relationship with weight is

              N / W = 1.76 10³/( 60 9.8)

              N / W = 3

normal is three times greater than body weight

e) the answer is reasonable since by Newton's first law the body must continue in a straight line, therefore to change its trajectory a force must be applied to deflect it

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