The organic particles are molecules. Because of strong covalent bonding in the molecule, organic compounds do not react quickly. Reactions with organic compounds are generally slower than inorganic reactions due to this fact.
Increasing temperature speeds up a reaction because of there being more collisions and those collisions have higher energy. Also the high concentration of the chemicals, particle size and there being a suitable catalyst present. ( Though this process is harmful should it be used in modifying results in food grains and meats.)
Answer:742 torr= approximately 0.976 atm
Explanation:
Since we know that one atm= 760 torr, we can compute the following calculation:
(742 torr/1)*(1atm/760torr)=0.976316 atm
Remember sig figs (3) to round it to 0.976 atm
*
=0.976316=0.976 atm
(torr cancels out and we're left with atm)
Hope this helps :)
Answer:
It is a example of erosion
Explanation: because pieces of rock erode making it unstable a causes a landslide
I found this is the order of activity in Internet
Mn>Zn>Cr>Fe>Cd>Co>Ni>Pb
You can see that Fe is between Cr and Cd
Cr is more active than Fe and Fe is more active than Cd.
The Fe will displace Cd but not Cr.
Answer:Fe
Answer:

Explanation:
Moles of SO₃ = 0.760 mol
Volume = 1.50 L


[SO₃] = 0.5067 M
Considering the ICE table for the equilibrium as:

Given:
Equilibrium concentration of O₂ = 0.130 mol
Volume = 1.50 L


[O₂] = x = 0.0867 M
[SO₂] = 2x = 0.1733 M
[SO₃] = 0.5067-2x = 0.3334 M
The expression for the equilibrium constant is:
