Answer:
I think it's B
Explanation:
I dont have much experience with the periodic table, but I just think its B.
2.4(10^3)
=2.4*10^3
=2.4*(10*10*10)
=2400 <span>milliliters
To </span>centiliters is<span> 2400mL= <u>240.0000cl. </u> </span>
The correct answer of the given question above would be a PICTOGRAM. OSHA’s required pictograms must be in the shape of a square set at a point and
include a black hazard symbol on a white background with a red frame sufficiently wide enough to
be clearly visible.
Answer:
Type of hybridisation
Explanation:
For example , saturated hydrocarbons have sp3 hybridisation while unsaturated hydrocarbons have either sp2 or sp hybridisation.
Example: Ethane( C2H6) has sp3 hybridisation and ethene(C2H4) has sp2 hybridisation and Ethyne(C2H2) has sp hybridization.
Answer:
![[I_2]=[Br]=0.31M](https://tex.z-dn.net/?f=%5BI_2%5D%3D%5BBr%5D%3D0.31M)
Explanation:
Hello there!
In this case, according to the given information, it is possible for us to set up the following chemical equation at equilibrium:
Now, we can set up the equilibrium expression in terms of x (reaction extent) whereas the initial concentration of both iodine and bromine is 0.5mol/0.250L=2.0M:
![K=\frac{[IBr]^2}{[I_2][Br_2]} \\\\1.2x10^2=\frac{(2x)^2}{(2.0-x)^2}](https://tex.z-dn.net/?f=K%3D%5Cfrac%7B%5BIBr%5D%5E2%7D%7B%5BI_2%5D%5BBr_2%5D%7D%20%5C%5C%5C%5C1.2x10%5E2%3D%5Cfrac%7B%282x%29%5E2%7D%7B%282.0-x%29%5E2%7D)
Thus, we solve for x as show below:
Therefore, the concentrations of both bromine and iodine are:
![[I_2]=[Br]=2.0M-1.69M=0.31M](https://tex.z-dn.net/?f=%5BI_2%5D%3D%5BBr%5D%3D2.0M-1.69M%3D0.31M)
Regards!
