Na₂O is an ionic compound. Na is in group 1 which means it has one electron in the outer shell. O is in group 6 so it has 6 electrons in the outer shell.
To become stable atoms need to either lose the electrons in the outer shell or gain electrons to gain a complete outer shell configuration.
To become stable Na loses its outer electron and becomes positively charged. It only loses one electron, so net charge is +1. O to become stable gains 2 electrons to complete its outer shell and becomes negatively charged. since it gains 2 electrons, the net charge is -2.
cation - Na⁺
anion - O²⁻
O gains 2 electrons but Na can give only one electron, therefore 2 Na⁺ ions are required.
the compound can be written by exchanging the charges
ions Na⁺ O²⁻
charge +1 -2
exchange Na₂O
Correct answer is <span>Na has +1 charge and O has -2 charge</span>
Answer:
Kf = 9.96x10⁴¹
Explanation:
When Fe³⁺ and CN⁻ are in water, complex Fe(CN)₆³⁻ is formed, thus:
Fe³⁺ + 6CN⁻ ⇄ Fe(CN)₆³⁻
Kf is defined as:
Kf = [Fe(CN)₆³⁻] / [Fe³⁺] [CN⁻]⁶
Equilibrium concentration of ions is:
[Fe(CN)₆³⁻] = 1.5x10⁻³M
[Fe³⁺] = 8.5x10⁻⁴⁰
[CN⁻] = [KCN] = 0.11M
Replacing in Kf expression:
Kf = [1.5x10⁻³M] / [8.5x10⁻⁴⁰] [ 0.11M]⁶
<h3>Kf = 9.96x10⁴¹</h3>
Answer:
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