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3 years ago

5

The direct transfer of heat from one substance to another substance that it is touching is called

2 answers:

Oksanka [162]3 years ago

6 0

Thermal energy is the direct transfer of heat from one substance to another

Allushta [10]3 years ago

5 0

The correct answer is conduction because you are conducting the heat through something like a finger etc.

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If excess ammonium sulfate reacts with 20.0g of calcium hydroxide how many grams of ammonia are produced

bagirrra123 [75]

The reaction between ammonium sulfate and calcium hydroxide is given below.
(NH₄)₂SO₄ + Ca(OH)₂ --> 2NH₃ + CaSO₄ + 2H₂O
From the balance equation, we can conclude that every 74 g of calcium sulfate reacted with enough amount of ammonium sulfate will yield 34 grams of ammonia. From the given amount,
(20 g calcium sulfate) x (34 grams ammonia / 74 g calcium sulfate)
= <em>9.19 g ammonia</em>

3 0

4 years ago

A student placed 18.5 g of glucose (C6H12O6) in a volumetric flask, added enough water to dissolve the glucose by swirling, then

mamaluj [8]

Answer:

1.30464 grams of glucose was present in 100.0 mL of final solution.

Explanation:

$Molarity=\frac{moles}{\text{Volume of solution(L)}}$

Moles of glucose = $\frac{18.5 g}{180 g/mol}=0.1028 mol$

Volume of the solution = 100 mL = 0.1 L (1 mL = 0.001 L)

Molarity of the solution = $\frac{0.1028 mol}{0.1 L}=1.028 mol/L$

A 30.0 mL sample of above glucose solution was diluted to 0.500 L:

Molarity of the solution before dilution = $M_1=1.208 mol$

Volume of the solution taken = $V_1=30.0 mL$

Molarity of the solution after dilution = $M_2$

Volume of the solution after dilution= $V_2=0.500L = 500 mL$

$M_1V_1=M_2V_2$

$M_2=\frac{M_1V_1}{V_2}=\frac{1.208 mol/L\times 30.0 mL}{500 mL}$

$M_2=0.07248 mol/L$

Mass glucose are in 100.0 mL of the 0.07248 mol/L glucose solution:

Volume of solution = 100.0 mL = 0.1 L

$0.07248 mol/L=\frac{\text{moles of glucose}}{0.1 L}$

Moles of glucose = $0.07248 mol/L\times 0.1 L=0.007248 mol$

Mass of 0.007248 moles of glucose :

0.007248 mol × 180 g/mol = 1.30464 grams

1.30464 grams of glucose was present in 100.0 mL of final solution.

4 0

4 years ago

Pls help I’m in a test plssss

____ [38]

Answer:

6

Explanation:

6

5 0

3 years ago

Calculate a pendulums frequency (in Hz) if the pendulum completes 19 cyclesin 0.5 s.

MAVERICK [17]

1Hz = 1 cycle per second

19 cycles / .5 seconds = 38Hz

8 0

3 years ago

13) Methane (CH4) combines with oxygen according to the balanced equation below. What is the limiting reactant if 25.0 g of CH4

marissa [1.9K]

Answer:

Limiting reactant: Oxygen $O_2$

Explanation:

First write the balanced chemical equation:

$CH_4 + 2 O_2 \rightarrow CO_2 + 2 H_2O$

$mole=\frac{given\, mass}{molecular\, mass}$

given mass of methane =25g

molecular mass of methane=16g/mol

mole=1.5625mol

given mass of oxygen=50

molar mass of oxygen=32g/mol

mole=1.5625mol

from the above balanced equation it is clearly that,

1 mole of methane needs 2 moles of oxygen for complete reaction

Therefore,

1.5625 moles of methane needs 3.125 moles of oxygen for complete reaction but we have only 1.5625 moles of oxygen,

hence,

oxygen will be the limiting reactant and methane will be the excess reactant

8 0

3 years ago