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maria [59]
3 years ago
14

A 35kg cannonball sits at rest on a flat level surface. What is the normal force exerted on the cannon ball. Use -9.8 m/s2 for a

cceleration due to gravity.
A. -343N

B. 44.8N

C. 25.2N

D. 343N
Physics
1 answer:
Tom [10]3 years ago
8 0

Answer:

a) N = 343 [N]

Explanation:

We must remember Newton's third law, which tells us that the force acting on a body is equal to the normal reaction force of equal magnitude but acting in the opposite direction.

N=m*g

where:

m = mass = 35 [kg]

g = gravity acceleration = 9.81 [m/s²]

N = 35*9.8\\N= 343 [N]

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A fixed 11.2-cm-diameter wire coil is perpendicular to a magnetic field 0.53 T pointing up. In 0.10 s , the field is changed to
Karolina [17]

Answer:

The average induced emf in the coil is 0.0286 V

Explanation:

Given;

diameter of the wire, d = 11.2 cm = 0.112 m

initial magnetic field, B₁ = 0.53 T

final magnetic field, B₂ = 0.24 T

time of change in magnetic field, t = 0.1 s

The induced emf in the coil is calculated as;

E = A(dB)/dt

where;

A is area of the coil = πr²

r is the radius of the wire coil = 0.112m / 2 = 0.056 m

A = π(0.056)²

A = 0.00985 m²

E = -0.00985(B₂-B₁)/t

E = 0.00985(B₁-B₂)/t

E = 0.00985(0.53 - 0.24)/0.1

E = 0.00985 (0.29)/ 0.1

E = 0.0286 V

Therefore, the average induced emf in the coil is 0.0286 V

3 0
3 years ago
When a person floating in swimming pool, they experience an upthrust. what causes this effect?​
velikii [3]
When your head sticks out of the water the upthrust reduces as your head is no longer displacing water, and there is 0 resultant force so you float at that level. hope this helps, can i get brainliest please
6 0
3 years ago
As a ship comes into view over the horizon the top appears before the rest of the ship how does this demonstrate the earth is sp
valina [46]
Since its a sphere, the top is seen first because its the tallest part if the ship. If the earth was flat, the whole ship would be seen.
7 0
3 years ago
In the Biomedical and Physical Sciences building at MSU there are 135 steps from the ground floor to the sixth floor. Each step
satela [25.4K]

Answer:

W = 16.5 Kj

P = 49.9 Watt

E = 16471

Explanation:

m = 73.5kg

t = 5min 30sec = (5×60) + 30 = 330sec

each step = 16.6cm = 0.166m

h = 135×0.166 = 22.41 m

g = 10 m/s²

(i) W = F × s = W × h = mgh

W = 73.5×10×22.41 = 16471.35

W = 16.5 Kj

(ii) Power = workdone/time

P = 16471.35/330

P = 49.9 Watt

(iii) The energy burnt in this process = 16471

4 0
3 years ago
Suppose two children push horizontally, but in exactly opposite directions, on a third child in a wagon. The first child exerts
tangare [24]

Answer:

Value of acceleration in each case is  7.52\ m/s^2 \ and \ 7.14\ m/s^2.

Explanation:

According to newton's law :

F_{net} = ma       ...equation 1.

In the given case, F_{net}= Force by both the children - Friction force .

F_{net} = (75+95)-12=158\ N.

Putting value of F in equation 1.

a=\dfrac{F_{net}}{m}=\dfrac{158}{21}=7.52\ m/s^2.

Now, if friction force = 20 N.

Therefore, F_{net}=(75+95)-20=150\ N.

Putting value of F and a in equation 1.

a=\dfrac{F_{net}}{m}=\dfrac{150}{21}=7.14\ m/s^2.

Hence , this is the required solution.

8 0
3 years ago
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