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maria [59]
2 years ago
14

A 35kg cannonball sits at rest on a flat level surface. What is the normal force exerted on the cannon ball. Use -9.8 m/s2 for a

cceleration due to gravity.
A. -343N

B. 44.8N

C. 25.2N

D. 343N
Physics
1 answer:
Tom [10]2 years ago
8 0

Answer:

a) N = 343 [N]

Explanation:

We must remember Newton's third law, which tells us that the force acting on a body is equal to the normal reaction force of equal magnitude but acting in the opposite direction.

N=m*g

where:

m = mass = 35 [kg]

g = gravity acceleration = 9.81 [m/s²]

N = 35*9.8\\N= 343 [N]

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alex41 [277]
Given:

Uniform distributed load with an intensity of W = 50 kN / m on an overhang beam.

We need to determine the maximum shear stress developed in the beam:

τ = F/A

Assuming the area of the beam is 100 m^2 with a length of 10 m.

τ = F/A
τ = W/l
τ = 50kN/m / 10 m
τ = 5kN/m^2
τ = 5000 N/ m^2<span />
8 0
3 years ago
A certain car traveling at 97 km/h can stop in 47 m on a level road find the coefficient of friction
IrinaVladis [17]

The coefficient of friction between the road and the car's tire is determined as 0.78.

<h3>Acceleration of the car</h3>

The acceleration of the car is calculated as follows;

v² = u² - 2as

0 = u² - 2as

a = u²/2s

where;

  • u is the initial velocity = 97 km/h = 26.94 m/s

a = (26.94)²/(2 x 47)

a = 7.72 m/s²

<h3>Coefficient of friction</h3>

μ = a/g

μ = (7.72)/9.8

μ = 0.78

Learn more about coefficient of friction here: brainly.com/question/14121363

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5 0
1 year ago
Which is not a common property of ionic compounds?
Dmitriy789 [7]

Answer:

low melting point

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Explanation:

8 0
3 years ago
A 1400 kg wrecking ball hangs from a 20-m-long cable. the ball is pulled back until the cable makes an angle of 30.0 ∘ with the
anastassius [24]

From the geometry of the problem, the 20 m-long cable creates the hypotenuse of a right triangle, with the extended of the other two sides of size 20 m * cos(30 deg), which is around 17.3 m. Therefore, the ball has increased by 20 m - 17.3 m = 2.7 m. 

The potential energy will have altered by m*g*h, which is 1400 kg * 9.8 m/s^2 * 1.6 m , or about 37044 joules.

5 0
3 years ago
Read 2 more answers
The distance, x, covered by a particle in time, t, is given as x=a +bc+ct^2 +dt^3
Sav [38]

Answer:

a has units of distance

b  has units of distance over time

c  has units of distance over time^2

d has units of distance over time^3

Explanation:

Since the expression for the distance is:

x = a+b\,t+c\,t^2+d\,t^3

then:

a has units of distance

b  has units of distance over time

c  has units of distance over time^2

d has units of distance over time^3

because we are supposed to be able to add all of the terms and get a distance.  So the products on each term that contains factors of time (t) should be cancelling those time units with units in the denominator of the multiplicative constant s that accompany them.

6 0
3 years ago
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