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3 years ago

Which measurement is equivalent to 350 milliliters?

1 answer:

4 0

350 milliliters equals to .35 liters
Therefore, 3.5 times 10^-1 would be the only correct answer since that is the only one that matches .35 liters

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Could you guys tell me whether the photo represents a balanced or unbalanced equation

NARA [144]

Answer:

that is preatty balenced m8

Explanation:

6 0

4 years ago

What quantity is measured on the x-axis of a position vs. time graph.

tensa zangetsu [6.8K]

Answer:

Velocity

Explanation:

7 0

3 years ago

After fracture, the total length was 47.42 mm and the diameter was 18.35 mm. Plot the engineering stress strain curve and calcul

Fittoniya [83]

Answer:

Part a: <em>The value of yield strength at 0.2% offset is obtained from the engineering stress-strain curve which is given as 274 MPa.</em>

Part b: <em>The value of tensile strength is obtained from the engineering stress-strain curve which is given as 417 MPa</em>

Part c: <em>The value of Young's modulus at given point is 172 GPa.</em>

Part d: <em>The percentage elongation is 18.55%.</em>

Part e: The percentage reduction in area is 15.81%

Explanation:

From the complete question the data is provided for various Loads in ductile testing machine for a sample of d0=20 mm and l0=40mm. The plot is drawn between stress and strain whose values are calculated using following formulae. The corresponding values are attached with the solution.

The engineering-stress is given as

$\sigma=\frac{F}{A}\\\sigma=\frac{F}{\pi \frac{d_0^2}{4}}\\\sigma=\frac{F}{\pi \frac{(20 \times 10^-3)^2}{4}}\\\sigma=\frac{F}{3.14 \times 10^{-4}}$

Here F are different values of the load

Now Strain is given as

$\epsilon=\frac{l-l_0}{l_0}\\\epsilon=\frac{\Delta l}{40}\\$

So the curve is plotted and is attached.

<em>The value of yield strength at 0.2% offset is obtained from the engineering stress-strain curve which is given as 274 MPa.</em>

<em>The value of tensile strength is obtained from the engineering stress-strain curve which is given as 417 MPa</em>

Young's Modulus is given as

$E=\frac{\sigma}{\epsilon}\\E=\frac{238 /times 10^6}{0.00138}\\E=172,000 MPa\\E=172 GPa$

<em>The value of Young's modulus at given point is 172 GPa.</em>

The percentage elongation is given as

$Elongation=\frac{l_f-l_0}{l_0} \times 100\\Elongation=\frac{47.42-40}{40}\times 100\\Elongation=18.55 \%\\$

So the percentage elongation is 18.55%

The reduction in area is given as

$Reduction=\frac{A_0-A_n}{A_0} \times 100\\Reduction=\frac{\pi \frac{d_0^2}{4}-\pi \frac{d_n^2}{4}}{\pi \frac{d_0^2}{4}}\times 100\\Reduction=\frac{{d_0^2}-{d_n^2}}{{d_0^2}} \times 100\\Reduction=\frac{{20^2}-{18.35^2}}{{20^2}} \times 100\\Reduction=15.81\%$

So the reduction in area is 15.81%

6 0

3 years ago

Which of the following would decrease current flow in a circuit made originally from a 6-volt battery, a loop of wire, and a swi

Oduvanchick [21]

For a given closed circuit the current voltage and resistance of circuit is related with ohm's law

$V = i*R$

here

V = voltage difference due to battery

i = current flow in the circuit

R = resistance

so from above equation

$i = \frac{V}{R}$

so in order to decrease the current in the circuit we can either increase the resistance of the circuit or decrease the voltage

Now the formula of resistance is

$R =\rho \frac{L}{A}$

here

$\rho$ = resistivity of material of resistance

$L = resistance$

A = crossectional area

a) if we use a thick wire the as per above formula of resistance the value of resistance will decrease.

And hence the current will increase in the circuit so it is not correct option

b) If 6V battery is replaced by 12 V battery then due to increase in potential difference the current in the circuit will also increase, so this is not correct answer.

c)Opening the switch will decrease the voltage from 6 V to 0 Volt

due to this decrease in potential difference the current in the circuit will also decrease. So by Opening the switch the current will be decreased in this circuit.

8 0

3 years ago

A Chinook salmon can swim underwater at 3.75 m/s, and it can also jump vertically upward, leaving the water with a speed of 6.20

Olin [163]

Answer:

P = 2161 N

Explanation:

For this exercise, let's start with Newton's second law

P - W = m a

P = ma + W

Where P is the fin force, W the weight,

Let's look for the vertical acceleration of the fish, this goes from a vertical speed of zero to a speed of 6.20 m / s when it has traveled half its length 1.50

y = 0.75 m

v² = v₀ + 2 a y

a = v² / 2 y

a = 6.20²/2 0.75

a = 25.63 m / s

We substitute in Newton's second law

P = m (g + a)

Let's calculate

P = 61.0 (0 9.8 + 25.63)

P = 2161 N

5 0

3 years ago