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maw [93]
3 years ago
5

1. If a house cost $200,000 in Las Vegas in 2012 and there was a 20.7% increase in houses from 2012 to 2013, what is the price o

f the house in 2013.?
Mathematics
2 answers:
Salsk061 [2.6K]3 years ago
5 0
241,400 is your answer
scZoUnD [109]3 years ago
3 0

Answer:

$241,400

Step-by-step explanation:

House costs: $200,000

Percentage increase: 20.7%

This means that the cost of the house increased by that percentage from 2012 to 2013. Therefore the following,

200,000 x 20.7/100 = 41,400

So the value of the house increased by $41,400 in this year.

Now we add to evaluate the total price of the house in 2013.

200,000 + 41,400 = 241,400

House price: $241,400

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Points A and B have coordinates (8, 3) and (p, q) respectively. The equation of the perpendicular
DaniilM [7]

Answer:

p = -4, q = -3

Step-by-step explanation:

y = -2x +4  ... (1)   perpendicular bisector of AB, slope = -2

slope of AB = 1/2

Line AB pass (8,3): (y-3) / (x-8) = 1/2

AB equation: y-3 = 1/2(x-8)      y = 1/2x - 1  ... (2)

(2)-(1): 5/2 x = 5      x = 2

y = 0       (2,0) intercept of bisector and AB, it is midpoint of A (8,3) and (p,q)

(8+p)/2 = 2

<u>p = -4</u>

(3+q)/2 = 0

<u>q = -3</u>

4 0
3 years ago
Really struggling with this, can someone please help me out and give me a brief explanation? Id greatly appreciate it.
dsp73

Answer:

jjjjjjjjjjjjjjjjjjjjj

Step-by-step explanation:

7 0
3 years ago
Use exponents to write an expression for one billion
kykrilka [37]
The anser would be 500 with the exponet of 100 solve my multiplying
5 0
3 years ago
What expression is equivalent to 12x^4/4x^16 helpppp
adoni [48]

Answer: 48x/64

Work (assuming ^ is multiplication):

12x^4/4x^16

12x ^ 4x = 48x

4 ^ 16 = 64

3 0
2 years ago
What is the sum of 20x^2-10x-30
ivann1987 [24]

Answer:

The sum of the roots is 0.5

Step-by-step explanation:

<u><em>The correct question is</em></u>

What is the sum of the roots of 20x^2-10x-30

we know that

In a quadratic equation of the form

ax^{2} +bx+c=0

The sum of the roots is equal to

-\frac{b} {a}

in this problem we have

20x^{2} -10x-30=0  

so

a=20\\b=-10\\c=-30

substitute

-\frac{(-10)} {20}=0.5

<u><em>Verify</em></u>

Find the roots of the quadratic equation

The formula to solve a quadratic equation is equal to

x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}

a=20\\b=-10\\c=-30

substitute

x=\frac{-(-10)\pm\sqrt{-10^{2}-4(20)(-30)}} {2(20)}

x=\frac{10\pm\sqrt{2,500}} {40}

x=\frac{10\pm50} {40}

x=\frac{10+50} {40}=1.5

x=\frac{10-50} {40}=-1

The roots are x=-1 and x=1.5

The sum of the roots are

-1+1.5=0.5 ----> is ok

5 0
3 years ago
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