False, there are many more types of Biomes
Answer:
Moles = Molecules / (6.0221415 x 10^23)
Explanation:
Answer:
127°C
Explanation:
This excersise can be solved, with the Charles Gay Lussac law, where the pressure of the gas is modified according to absolute T°.
We convert our value to K → -73°C + 273 = 200 K
The moles are the same, and the volume is also the same:
P₁ / T₁ = P₂ / T₂
But the pressure is doubled so: P₁ / T₁ = 2P₁ / T₂
P₁ / 200K = 2P₁ / T₂
1 /2OOK = (2P₁ / T₂) / P₁
See how's P₁ term is cancelled.
200K⁻¹ = 2/ T₂
T₂ = 2 / 200K⁻¹ → 400K
We convert the T° to C → 400 K - 273 = 127°C
BiO₃⁻ → Bi³⁺
+5 +3
Balance oxidation state:
BiO₃⁻ + 2 e⁻ → Bi³⁺
Balancing oxygen by adding water and balance H
BiO₃⁻ + 6 H⁺ + 2 e⁻ → Bi³⁺ + 3 H₂O
balance charge:
BiO₃⁻ + 6 H⁺ + 2 e⁻ → Bi³⁺ + 3 H₂O
+ 3 + 3
Final:
BiO₃⁻ + 6 H⁺ + 2 e⁻ → Bi³⁺ + 3 H₂O
Answer: -
8.00 g
The law of conservation of mass
Explanation: -
When magnesium burns in air it combines with oxygen to form magnesium oxide.
The mass of the product is the mass of the magnesium oxide.
The mass of the reactant is the mass of the magnesium + mass of the oxygen.
Since matter cannot be created or destroyed according to the law of conservation of mass,
Mass of Magnesium oxide formed = mass of magnesium reacted + mass of oxygen reacted
= 3.00 g + 5.00 g
= 8.00 g
