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3 years ago

Calculate the moles of argon gas at STP in 33 L. Round answer to 2 significant figures.

Chemistry

1 answer:

babymother [125]3 years ago

4 0

Answer:

1.5 mol

Explanation:

Step 1: Given data

Volume of argon gas: 33 L

Standard temperature: 273.15 K

Standard pressure: 1 atm

Step 2: Calculate the moles corresponding to 33 L of argon at standard temperature and pressure (STP)

At STP, 1 mole of argon gas occupies 22.4 L.

33 L × 1 mol/22.4 L = 1.5 mol

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Name the process which takes place when propene gas molecules are converted into a giant molecule

marissa [1.9K]

Answer:

Polymerization, any process in which relatively small molecules, called monomers, combine chemically to produce a very large chainlike or network molecule, called a polymer. The monomer molecules may be all alike, or they may represent two, three, or more different compounds.

7 0

3 years ago

Pure iron, Fe , can be produced from an ore called hematite, Fe2O3 , by reaction with carbon at high temperatures. 2Fe2O3+3C⟶4Fe

Sophie [7]

70 tons of hematite (Fe₂O₃) is needed to produce 49 tons of iron (Fe).

We'll begin by calculating the tons of hematite (Fe₂O₃) that reacted and the tons of Fe produced from the balanced equation. This is illustrated below:

2Fe₂O₃ + 3C —> 4Fe + 3CO₂

Molar mass of Fe₂O₃ = (56×2) + (16×3) = 160 g/mol

Mass of Fe₂O₃ from the balanced equation = 2 × 160 = 320 g

Divide by 907185 to express in ton

320 / 907185 = 0.000353 ton

Molar mass of Fe = 56 g/mol

Mass of Fe from the balanced equation = 56 × 4 = 224 g

Divide by 907185 to express in ton

224 / 907185 = 0.000247 ton

<h3>SUMMARY </h3>

From the balanced equation above,

0.000353 ton of Fe₂O₃ reacted to produce 0.000247 ton of Fe.

Finally, we shall determine the tons of hematite (Fe₂O₃) needed to produce 49 tons of Fe. This can be obtained as follow:

From the balanced equation above,

0.000353 ton of Fe₂O₃ reacted to produce 0.000247 ton of Fe.

Therefore,

X ton of Fe₂O₃ will react to produce 49 tons of Fe i.e

X ton of Fe₂O₃ = $\frac{0.000353 * 49}{0.000247} \\\\$

X ton of Fe₂O₃ = 70 tons

Thus, 70 tons of hematite (Fe₂O₃) is needed to produce 49 tons of Fe.

Learn more: brainly.com/question/15343472

5 0

3 years ago

Density Practice

Angelina_Jolie [31]

Answer:

1) mass and volume

2) float.

3) Sink

4) Apples

5) Cannonball

Explanation:

1) Density is based on the mass and volume of a material.

2) A material or an object with low density than water or liquid tends to float.

3) A material or an object with high density than water or liquid tends to sink.

4) The apples in the water have less density as they are floating in the water.

5) The cannonball is more dense than the ocean water and the ball sink in the less density water.

4 0

3 years ago

Gaseous ethane will react with gaseous oxygen to produce gaseous carbon dioxide and gaseous water . Suppose 9.02 g of ethane is

miv72 [106K]

Answer:

3.13g

Explanation:

First, we'll begin by writing a balanced equation between the reaction of gaseous ethane with gaseous oxygen to produce gaseous carbon dioxide and gaseous water. This is illustrated below:

2C2H6 + 7O2 —> 4CO2 + 6H2O

Next, let us calculate the mass of C2H6 and the mass of O2 that reacted from the balanced equation. This is illustrated below:

Molar Mass of C2H6 = (12x2) + (6x1) = 24 + 6 = 30g/mol

The mass of C2H6 that reacted from the balanced equation = 2 x 30 = 60g

Molar Mass of O2 = 16x2 = 32g/mol

Mass of O2 that reacted from the balanced equation = 7 x 32 = 224g

Now, to calculate the left over mass of ethane (C2H6), let us first calculate the mass of ethane (C2H6) that will react with 22g of oxygen(O2). This can be achieved by doing the following:

From the balanced equation above,

60g of C2H6 reacted with 224g of O2.

Therefore, Xg of C2H6 will react with 22g of O2 i.e

Xg of C2H6 = (60 x 22)/224

Xg of C2H6 = 5.89g

From the calculations above, 5.89g will react completely with 22g of O2.

The left over mass of C2H6 can be obtained as follow:

Mass of C2H6 from the question = 9.02g

Mass of C2H6 that reacted = 5.89g

The left over mass of C2H6 =?

The left over mass of C2H6 = Mass of C2H6 - mass of C2H6 that reacted

Left over mass of C2H6 = 9.02 - 5.89

Left over mass of C2H6 = 3.13g

7 0

3 years ago

You are performing an experiment in a lab to attempt a new method of producing pure elements from compounds. The only problem is

Verdich [7]

You need to calculate the atomic weight of that element.

number of moles = mass / atomic weight

atomic weight = mass / number of moles

atomic weight = 209.1 / 3 = 69.7 g/mol

The element produced will be gallium, Ga.

6 0

4 years ago

Read 2 more answers