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olga55 [171]
3 years ago
7

What ion charge patterns are in the periodic table

Chemistry
1 answer:
Rzqust [24]3 years ago
8 0
<span>the elements in groups1a, 2a, 3a have positive charges according to their group numbers</span>
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What is meant by conversion of energy
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the process of changing one form of energy into another

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The concentration of a salt solution in terms of mass by mass percentage is 20% and the mass of the solution is 500g determine t
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100 grams of solute would be present as 20% of 500 is 100
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Consider the equation:
Dmitry [639]

Answer:1. Rate=k[CHCl_3]^1[Cl_2]^\frac{1}{2}

2. The rate constant (k) for the reaction is 3.50M^\frac{-1}{2}s^{-1}

Explanation:

Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.

rate=k[CHCl_3]^x[Cl_2]^y

k= rate constant

x = order with respect to CHCl_3

y = order with respect to Cl_2

n = x+y= Total order

1. a) From trial 1: 0.0035=k[0.010]^x[0.010]^y  (1)

From trial 2: 0.0069=k[0.020]^x[0.010]^y   (2)

Dividing 2 by 1 :\frac{0.0069}{0.035}=\frac{k[0.020]^x[0.010]^y}{k[0.010]^x[0.010]^y}

2=2^x,2^1=2^x therefore x=1.

b)  From trial 2: 0.0069=k[0.020]^x[0.010]^y   (3)

From trial 3: 0.0098=k[0.020]^x[0.020]^y   (4)

Dividing 4 by 3:\frac{0.0098}{0.0069}=\frac{k[0.020]^x[0.020]^y}{k[0.020]^x[0.010]^y}

1.4=2^y,2^{\frac{1}{2}}=2^y therefore y=\frac{1}{2}

rate=k[CHCl_3]^1[Cl_2]^\frac{1}{2}

2. to find rate constant using trial 1:

0.0035=k[0.010]^1[0.010]^\frac{1}{2}  

k=3.50M^\frac{-1}{2}s^{-1}

5 0
4 years ago
What is the movement of thermal energy?
V125BC [204]
Thermal energy is atype of movement energy wich is exist in equilibrium.
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3 years ago
The ph of a fruit juice is 2.2 . find the hydronium ion​ concentration, left bracket upper h 3 upper o superscript plus right br
patriot [66]

Answer:

[H₃O⁺] = 6.31 x 10⁻³ M.

Explanation:

  • To find the hydronium ion concentration [H₃O⁺], we can use the relation:

<em>pH = - log[H₃O⁺].</em>

<em></em>

∴ 2.2 = - log[H₃O⁺].

∴ log[H₃O⁺] = - 2.2

<em>∴  [H₃O⁺] = 6.31 x 10⁻³ M.</em>

3 0
3 years ago
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