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OLga [1]
3 years ago
13

Logically why would light move faster in vacuum than in a solid? *

Physics
1 answer:
AVprozaik [17]3 years ago
4 0

Answer:

The light moves the fastest in a solid because there are move particles and with more particles they are closer together than in a liquid or gas. A vacuum has no particles with no particles there is nothing to transfer the light.

Explanation:

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Angular oscillation of the slotted link is achieved by the crank OA, which rotates clockwise at the steady speed N = 118 rev/min
Leni [432]

Answer:

Angular velocity will be 65.3 rad/s

7 0
3 years ago
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_____ is the frictional force needed to slow down an object in motion
tekilochka [14]

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gravity

Explanation:

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4 years ago
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Which type of motion most accurately describes the behavior of a friction -less pendulum?
kaheart [24]

Answer:

B) Periodic Motion

Explanation:

When a pendulum is friction-less, i.e there are no damping forces acting on it, its motion will be periodic, i.e it will bob up and down going from potential energy to kinetic energy and back. Thus, the motion of the pendulum can be best described by the term "period motion", hence choice B.

If however, forces do act on the pendulum, and if they acts as to damp the pendulum, it will oscillate less and less as time goes by, and eventually come to a stop (in the real world this damping force is usually air resistance ). And if the force acts in such a way that it increases the oscillations, the pendulum will swing higher and higher, and the system will go haywire! :)

4 0
4 years ago
Lumbar nerves transmit signals that allow us to?
labwork [276]
Lumbar nerves transmit signals that allow us to walk. They are a pivotal part of the human body, and without them we would be immobile. Hope this helps.
7 0
4 years ago
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a student standing between two walls shouts once.he hears the first echo after 3 seconds and the next after 5 seconds. calculate
Karolina [17]

Explanation:

It took t_1 =1.5\:\text{s} for the sound to reach the 1st wall and at the same time time, the same sound took t_2 = 2.5\:\text{s} to reach the 2nd wall. Assuming that the sound travels at 343 m/s, then let x_1 be the distance of the person to the 1st wall and x_2 be the distance to the 2nd wall. So the distance between the walls X is

X = x_1 + x_2 = v_st_1 + v_st_2 = v_s(t_1 + t_2)

\:\:\:\:\:= (343\:\text{m/s})(4.0\:\text{s}) = 1372\:\text{m}

6 0
3 years ago
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