Answer:
=<em><u> 1.7 M</u></em>
Explanation:
Molecular mass of NaCl = ( 23+35.5 ) = 58.5g
58.5g of NaCl are weighed by 1 mole of NaCl
10.0g of NaCl will be weighed by ( 10÷58.5 )
<em> <u>= 0.17 moles of </u><u>NaCl</u></em>
100mL = ( 100÷1000)L = 0.1L
0.1L of a solution is occupied by 0.17 moles of NaCl
<u>1L</u> of solution will be occupied by [(1÷0.1)×0.17]
=<em><u>1</u></em><em><u>.</u></em><em><u>7</u></em><em><u> </u></em><em><u>M</u></em>
A because it is the only one that a formula doesnt tell
Answer : The oxidation state of nitrogen in
is, (+5)
Explanation :
Rules for the oxidation numbers :
- The oxidation number of a free element is always be zero.
- The oxidation number of a monatomic ion equal to the charge of the ion.
- The oxidation number of Hydrogen (H) is +1.
- The oxidation number of oxygen (O) in compounds is usually -2, but it is -1 in the peroxides.
- The oxidation number of a Group 1 element in a compound is +1.
- The oxidation number of a Group 2 element in a compound is +2.
- The oxidation number of a Group 17 element in a binary compound is -1.
- The sum of the oxidation numbers of all of the atoms in a neutral compound is zero.
- The sum of the oxidation numbers in a polyatomic ion is equal to the charge of the ion.
The given compound is,
Let the oxidation state of 'N' be, 'x'
Hence, the oxidation state of N is, (+5)