Answer:
0.934J/g°C
Explanation:
Using Q = mc∆T
However, in this question;
(Q)water = -(Q)metal
(mc∆T)water = -(mc∆T)metal
According to the information provided in the question;
For water;
m = mass = 72.9g
c = specific capacity of water = 4.184 J/g°C
∆T = 22.9 - 15.9 = 7°C
For metal;
m = mass = 45.7g
c = specific capacity of water = ?
∆T = 22.9 - 72.9 = -50°C
(mc∆T)water = -(mc∆T)metal
(72.9 × 4.184 × 7) = -(45.7 × c × -50)
2135.0952 = -(-2285c)
2135.0952 = 2285c
c = 2135.0952/2285
c of metal = 0.934J/g°C
Answer:
The six changes are: Freezing: the substance changes from a liquid to a solid. Melting: the substance changes back from the solid to the liquid. Condensation: the substance changes from a gas to a liquid.
Answer:
No.
Explanation:
There aren't any outright 'ionic acids', although some typical strong mineral acids can be seen as 'ionic' in character. For instance, some organic acids featuring a carbon chain have covalent bonding between their carbon atoms.
Answer:
1. 2.17 dm^3
2. 109.1 dm^3
3. 0.398 atm
Explanation:
1. Considering the equation of the reaction;
Number of moles of chlorine gas in 3.44 g= 3.44/2(35.5)= 0.0485 moles
Since we can see from the equation that
1 mole of chlorine gas yields 2(22.4) dm^3 of HCl
0.0485 moles of chlorine gas yields 0.0485 moles × 2(22.4)dm^3/1= 2.17 dm^3
2. Note that 1 mole of Kr occupies 22.4 dm^3
Therefore 4.87 moles of Kr will occupy 4.87 × 22.4 dm^3/1 = 109.1 dm^3
3. From PV= nRT
n= 0.0485 moles
V= 4.55 L
T= 455 K
P= the unknown
R= 0.082 atm dm^3K-1mol-1
P= nRT/V
P= 0.0485 moles × 0.082 atm dm^3K-1mol-1 × 455/4.55
P= 0.398 atm
Answer:
<h3>
Explanation:</h3>
In Analytical Chemistry chromatography is widely used for the separation of samples.
- In thin layer chromatography, the mixture of components are separated on the basis of their polarity.
- The solvent solution(mobile phase) that we use are non polar & silica gel( TLC paper made of/stationary phase) are polar.
- Consider the mixture we have taken consist of two samples having large polar difference.
- Due to opposite nature of silica gel(polar) & solvent solution (non polar) the movement become easy & due to capillary action solvent solution rise to the top.
- The mixture of sample we have taken, the sample have less polarity have high peak or they travel more distance than that of more polar sample when they dipped into the solution.
In the given diagram, mixture of 8 samples are separated on the basis of their polarity, the distance travelled by solvent is 35 mm, distance travelled by sample 1 is 11 mm & similarly distance travelled by sample 2,3,4,5,6,7 are 15,31,4,22,25,33 in mm respectively.
Rf Value: Rf value is retention factor which tells about relative absorption of each sample & range of Rf value is 0-1.
Formula to calculate Rf value is
Now, solving for Rf value of sample 1
<em>Given:</em>
Distance moved by sample 1 = 11 mm
Distance movedby solvent = 35 mm
<em>To find:</em>
Rf value of sample 1 = ?
<em>Solution:</em>
Substituting the given data in above formula,
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