Question

How many moles of KClO3 are needed to produce 480 grams of O2?

Answer 1

Answer:

2:3

You'd need 33.3 moles of potassium chlorate, KClO3 , to produce that much oxygen. Notice that you have a 2:3. mole ratio between potassium chlorate and oxygen gas, which means that, regardless of how many moles of the former react, you'll always produce 3/2 times more moles of the latter.

Explanation: