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inna [77]
3 years ago
10

Which compound plays an important role in leather processing and electroplating?

Chemistry
2 answers:
Margaret [11]3 years ago
7 0

<u>Answer;</u>

  • Hydrochloric acid

<u>Explanation;</u>

  • Hydrochlorc acid plays a vital role in leather processing and electroplating.
  • Hydrochloric acid has a number of important applications in real life these includes; fertilizers, and dyes, textile, in electroplating, rubber and in the photographic industries.
  • Electroplating is the process that involves coating a metal using another metal for the purpose of improving their appearance or preventing rusting.
  • Hydrochloric acids is used in the processing of leather or the tanning of leather process, in which tanneries use the acid to stop the growth of bacteria and also maintain proper pH.

abruzzese [7]3 years ago
5 0

Answer:

hydrochloric acid is the correct answer.

Explanation:

hydrochloric acid compound plays an important role in leather processing and electroplating.

Electroplating is a process in which metal is coated with a thin layer of another metal.hydrochoric acid is used in electroplating as it enables oxidation of copper and removes the copper ions from the solution.

Hydrochloric acid is used in leather processing because tanneries use hydrochloric acid to stop the growth of bacteria and to control the pH level of the leather.

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If 175mL of oxygen is produced at STP, how many grams of hydrogen peroxide, H2O2
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Answer:

0.53g

Explanation:

We'll begin by converting 175mL to L. This is illustrated below:

1000mL = 1L

Therefore 175mL = 175/1000 = 0.175L

Next, we shall calculate the number of mole of O2 that occupy 0.175L. This is illustrated below:

1 mole of O2 occupy 22.4L at stp.

Therefore, Xmol of O2 will occupy 0.175L i.e

Xmol of O2 = 0.175/22.4

Xmol of O2 = 7.81×10¯³ mole

Therefore, 7.81×10¯³ mole of O2 occupy 175mL.

Next, we shall determine the number of mole of H2O2 that decomposed to produce 7.81×10¯³ mole of O2. This is illustrated below:

2H2O2 —> 2H2O + O2

From the balanced equation above,

2 moles of H2O2 decomposed to produce 1 mole of O2.

Therefore, Xmol of H2O2 will decompose to produce 7.81×10¯³ mole of O2 i.e

Xmol of H2O2 = 2 x 7.81×10¯³

Xmol of H2O2 = 1.562×10¯² mole

Therefore, 1.562×10¯² mole of H2O2 decomposed in the reaction.

Finally, we shall convert 1.562×10¯² mole of H2O2 to grams. This is illustrated below:

Molar mass of H2O2 = (2x1) + (16x2) = 34g/mol

Mole of H2O2 = 1.562×10¯² mole

Mass of H2O2 =..?

Mole = mass /Molar mass

1.562×10¯² = mass /34

Cross multiply

Mass of H2O2 = 1.562×10¯² x 34

Mass of H2O2 = 0.53g

Therefore, 0.53g of Hydrogen peroxide, H2O2 were decomposition in the reaction.

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Who first arranged the elements according to nuclear charge?
vazorg [7]
Dmitri Mendeleev
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3 0
3 years ago
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2. A sample of gas has a pressure of 195 kPa and a volume of 3.50 L. If the pressure
zhannawk [14.2K]

Answer:

<h2>4.55 L</h2>

Explanation:

The new volume can be found by using the formula for Boyle's law which is

P_1V_1 = P_2V_2

Since we're finding the new volume

V_2 =  \frac{P_1V_1}{P_2}  \\

We have

V_2 =  \frac{195000 \times 3.5}{150000}  =  \frac{682500}{150000}  \\  = 4.55

We have the final answer as

<h3>4.55 L</h3>

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Answer:

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