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3 years ago

Which compound plays an important role in leather processing and electroplating?

Chemistry

2 answers:

Margaret [11]3 years ago

7 0

<u>Answer;</u>

Hydrochloric acid

<u>Explanation;</u>

Hydrochlorc acid plays a vital role in leather processing and electroplating.
Hydrochloric acid has a number of important applications in real life these includes; fertilizers, and dyes, textile, in electroplating, rubber and in the photographic industries.
Electroplating is the process that involves coating a metal using another metal for the purpose of improving their appearance or preventing rusting.
Hydrochloric acids is used in the processing of leather or the tanning of leather process, in which tanneries use the acid to stop the growth of bacteria and also maintain proper pH.

abruzzese [7]3 years ago

5 0

Answer:

hydrochloric acid is the correct answer.

Explanation:

hydrochloric acid compound plays an important role in leather processing and electroplating.

Electroplating is a process in which metal is coated with a thin layer of another metal.hydrochoric acid is used in electroplating as it enables oxidation of copper and removes the copper ions from the solution.

Hydrochloric acid is used in leather processing because tanneries use hydrochloric acid to stop the growth of bacteria and to control the pH level of the leather.

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Thermal energy naturally flows from _________ matter to _______ matter.

Firlakuza [10]

Answer:

Warmer

Cooler

Explanation:

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3 years ago

When aqueous magnesium chloride reacts with liquid bromine

Bingel [31]

Word equation: magnesium chloride + bromine -> magnesium bromide + chlorine
balance equation: MgCl2 + 2Br -> MgBr2 + 2Cl

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2 years ago

The bonds in the reactants of Figure 7-3 contained 372 kJ of chemical energy and the bonds in the products contained 350 kJ of c

satela [25.4K]

Answer: 22 kJ amount of energy is released in the following reaction.

Explanation: There are two types of reaction on the basis of amount of heat absorbed or released.

1. Endothermic reactions: These are the type of reactions in which reactants absorb heat to form the products. The energy of the reactants is less than the energy of the products.

2. Exothermic reactions: These are the type of reactions in which heat is released from the chemical reactions. The energy of the products is less than the reactants.

Sign convention for $\Delta H$ : This value is negative for exothermic reactions and positive for endothermic reactions.

For the given chemical reaction,

Energy of the products is less than the energy of the reactants, Hence, this reaction will be a type of exothermic reaction and energy will be released during this chemical change.

Amount of energy released = (350 - 372) kJ = -22kJ

Negative sign symbolizes the energy is being released. So, 22 kJ amount of energy is released in the following reaction.

6 0

3 years ago

Lead forms two compounds with oxygen. One contains 2.98g of lead and 0.461g of oxygen. The other contains 9.89g of lead and 0.76

aliina [53]

The given question is incomplete, the complete question is:

Lead forms two compounds with oxygen. One contains 2.98g of lead and 0.461g of oxygen. The other contains 9.89g of lead and 0.763g of oxygen. For a given mass of oxygen, what is the lowest whole-number mass ratio of lead in the two compounds that combines with a given mass of oxygen?

Answer:

The lowest whole-number mass ratio in the two compounds is 1:2.

Explanation:

There is a need to find the mole ratio between lead and oxygen atoms in order to find the whole-number mass ratio of lead in the two compounds. In the first compound, the given mass of lead is 2.98 grams, the molar mass of lead is 207.2 gram per mole.

The no. of moles can be determined by using the formula,

moles = mass/molecular mass

moles = 2.98 g/207.2 g/mol

= 0.0144 moles

The mass of oxygen in the compound I is 0.461 grams, the molecular mass of oxygen is 16 gram per mol.

moles = 0.461 g /16 g/mol

= 0.0288 moles

The ratio between the lead and oxygen in the compound I is 0.0144/0.0288 = 1:2

On the other hand, in the compound II, the mass of lead given is 9.89 grams, therefore, the moles of lead in compound II is,

moles = 9.89 g / 207.2 g/mol

= 0.0477 moles

The mass of oxygen given in compound II is 0.763 grams, the moles of oxygen present in the compound II is,

moles = 0.763 g / 16 g

= 0.0477 moles

The ratio between the lead and oxygen in the compound II is, 0.0477 moles lead /0.0477 moles oxygen = 1:1

Hence, of the two compounds, the lowest ratio is found in the compound I, that is, 1:2.

4 0

3 years ago

1. What do producers do, and what is another name for them?

Neko [114]

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3 years ago