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nirvana33 [79]
3 years ago
11

*deleting* lol sorryrryrioa

Physics
2 answers:
Aleksandr [31]3 years ago
8 0

Answer:

wut

Explanation:

kicyunya [14]3 years ago
3 0

Answer:

Huh? otay....

Explanation:

Brainliest?????????

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3. Pedro threw a penny into a fountain and it sank to the bottom. Which of the following would explain
____ [38]

Answer:

its B because we're not talking about mass even tho most people would have chosen A cuz it says mass and u they would think its apart of density but if ur testing to see density ur figuring out which object will sink and which one will float so da reason why da penny snuck it cuz da density is greater den da water and copper has a better chance of sinking den floating so dats why its B I hope dis helps :3

3 0
3 years ago
Read 2 more answers
In a pendulum system, when is it possible for the potential and kinetic energies both to be equal to zero
muminat
That's ONLY true when the pendulum is hanging
in the center position and not moving.
8 0
3 years ago
Need help please!! I literally am dumb and can’t do this
natta225 [31]

Answer:

The answer should be A and B. I don't fully know so don't quote me on that! Haha.

Explanation:

6 0
3 years ago
A small sculpture made of brass (rho brass = 8470 kg/m 3 ) is believed to have a secret central cavity. The weight of the sculpt
GaryK [48]

Answer:

Volume of secret cavity = 4 x 10⁻⁶m³

Explanation:

The weight of the sculpture in air is 15.76 N

Mass of the sculpture = 1.61 kg

Mass = Volume x Density

1.61 = V x 8470

Volume of brass =1.90 x 10⁻⁴ m³

When it is submerged in water, the weight is 13.86 N.

That is

  Weight of sculpture - Weight of water displaced = 13.86 N

  15.76 - Weight of water displaced = 13.86

   Weight of water displaced = 1.9 N

   Mass of water displaced = 0.194 kg

 Mass = Volume x Density

  0.194 = V x 1000

  Volume of water displaced =1.94 x 10⁻⁴ m³

Volume of secret cavity =  Volume of water displaced - Volume of brass material

Volume of secret cavity = 1.94 x 10⁻⁴-1.94 x 10⁻⁴ = 0.04x 10⁻⁴ = 4 x 10⁻⁶m³

7 0
3 years ago
It is found experimentally that the electric field in a certain region of Earth's atmosphere is directed vertically down. At an
Maru [420]

Answer:

q=7.965*10^-^6C

Explanation:

From the question we are told that

Altitude of  d_1 390m

MagnitudeM_1=60.0 N/C

Altitude of d_2=240 m

Magnitude is M_2= 100 N/C

Distance of cube d_c=150 m

Generally the flux \phi is mathematical given as

 \phi=60(150)^2cos180+100(150)^2*cos0

 \phi=-9*10^5

Generally Quantity of charge  q is mathematically given as

 q=\varepsilon _0 *\phi

 q=8.85*10^-^1^2 *9*10^5

 q=7.965*10^-^6C

5 0
2 years ago
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