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Paladinen [302]
3 years ago
6

What happens to the electrostatic force between two charged particles if the distance between them is doubled?

Physics
1 answer:
Stells [14]3 years ago
5 0

According to Coulomb's Law , The size of the force varies inversely as the square of the distance between the two charges. So ,if the distance between the two charges is doubled, the  electrostatic force will become weak by one fourth of the original force.

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Given: Saturated air changes temperature by 0.5°C/100 m. The air is completely saturated at the dew point. The dew point has bee
erma4kov [3.2K]

Answer:

Explanation:

Given

saturated air temperature by 0.5^{\circ}C/100 m

Dew point temperature is given by t=2^{\circ}C

Dew point is defined as the temperature after which air no longer to uphold the water vapor fuse with it and some water vapor may condense to a liquid.

air continues to rise for 1400 m

i.e. change in temperature would be \Delta t =\frac{0.5}{100}\times 1400=7^{\circ}C

Final temperature t_f

t_f+\Delta t=t

t_f=2-7=-5^{\circ}C

3 0
3 years ago
An automobile slows from 26 m/s to 18 m/s. Its acceleration is −2.0 m/s 2 . How much time does it take for the vehicle to slow d
Serggg [28]

Answer:4.0s

Explanation:jus is

4 0
3 years ago
An object of volume 0.0004m^3 and density 6000kg/m^3 is immersed inside a fluid of density 5000kg/m^3. The force exerted by the
FromTheMoon [43]

We have that the density of the fluid is

\rho_f=178.57  kg/m3

From the question we are told that

object of volume 0.0004m^3

density 6000kg/m^3

fluid of density 5000kg/m^3.

Force F=0.7N

Generally the equation for the Force   is mathematically given as

F= v*\rho_f*g\\\\0.7= 0.0004*\rho_f*9.8\\\\\rho_f=\frac{0.7}{0.0004*9.8}

\rho_f=178.57  kg/m3

For more information on this visit

brainly.com/question/13338592?referrer=searchResults

8 0
3 years ago
Radar uses radio waves of a wavelength of 2.2 m . The time interval for one radiation pulse is 100 times larger than the time of
liq [111]

Answer:

<em>The shortest distance to an object that this radar can detect would be </em>

<em>111 m</em>

Explanation:

The shortest distance is the minimum distance that would be detected by the radar, The time of oscillation can be obtained thus;

T = 1/f   ..........1

but f= v/λ substituting f into equation 1 we have;

T = λ/v...............2

Where λ is the wavelength = 2.2 m

v is the velocity of  light  since the radar is an electromagnetic wave

   = 3 x10^{8} m/s

T = 2.2 m / 3 x10^{8} m/s

T = 7.33 x10^{-9} s

<u>Calculating the time interval required by the pulse</u>

Since the interval of the pulse (t) is 100 times greater than the period of oscillation, the time of the pulse is expressed as;

t = 100 x T

t = 100 x 7.33 x10^{-9} s

t = 7.33 x 10^{-7} s

Therefor the time of the pulse is 7.33 x 10^{-7} s

<u>Calculating for the shortest distance of the radar</u>

The shortest distance of the radar can be obtained using the equation below;

λ_s = (t/2) x v ............3

Substituting into equation 3 we have

λ_s = (7.33 x 10^{-7} /2) x 3 x10^{8} m/s

λ_s  =  111 m

Therefore the shortest distance to an object that this radar can detect would be 111 m

   

8 0
4 years ago
How is the medium of a wave and transmit of a wave similar and different?
zepelin [54]

Answer:

Sound and light are similar in that both are forms of energy that travel in waves. They both have properties of wavelength, freqency and amplitude. Here are some differences: Sound can only travel through a medium (substance) while light can travel through empty space.

3 0
3 years ago
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