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4 years ago

What happens to the electrostatic force between two charged particles if the distance between them is doubled?

1 answer:

5 0

According to Coulomb's Law , The size of the force varies inversely as the square of the distance between the two charges. So ,if the distance between the two charges is doubled, the electrostatic force will become weak by one fourth of the original force.

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Whenever you push an object across a frictional surface, it starts out taking a lot of force to push to get the object moving. H

son4ous [18]

Answer:

The answer is A

Explanation:

Here's an example. A child is in school taking a test. They have made a mistake on a question, and want to erase it. The eraser is made out of a type of rubber, the rubber has friction, which means the eraser has something that's going to resist movement. Now the child has exerted enough force to get it moving, and it's moving, it won't stop unless the child stops exerting force to keep it moving. Both Newton's 1st and 3rd law explain the action of moving something on a surface with friction.

5 0

3 years ago

Use Stefan's law to find the intensity of the cosmic background radiation emitted by the fireball of the Big Bang at a temperatu

Rus_ich [418]

Complete Question

Use Stefan's law to find the intensity of the cosmic background radiation emitted by the fireball of the Big Bang at a temperature of 2.81 K. Remember that Stefan's Law gives the Power (Watts) and Intensity is Power per unit Area (W/m2).

Answer:

The intensity is $I = 3.535 *10^{-6} \ W/m^2$

Explanation:

From the question we are told that

The temperature is $T = 2.81 \ K$

Now According to Stefan's law

$Power(P) = \sigma * A * T^4$

Where $\sigma$ is the Stefan Boltzmann constant with value $\sigma = 5.67*10^{-8} m^2 \cdot kg \cdot s^{-2} K^{-1}$

Now the intensity of the cosmic background radiation emitted according to the unit from the question is mathematically evaluated as

$I = \frac{P}{A}$

=> $I = \frac{\sigma * A * T^4}{A}$

=> $I = \sigma * T^4$

substituting values

$I = 5.67 *10^{-8} * (2.81)^4$

$I = 3.535 *10^{-6} \ W/m^2$

4 0

3 years ago

The speed of a shallow water wave varies with

Sergio039 [100]

So we want to know how does the speed of a shallow water wave varies. If the wavelength is large enough in comparison to the depth of the water, meaning the wavelength is 20 times longer than the depth of water, the speed of a shallow water wave is the square root of gravity times water depth or: v=√(g*d), where v is speed of the wave, g=9.81 m/s^2 and d is water depth.

5 0

3 years ago

A dart hits a dartboard and stops in 0.060 s. The net force on the dart is 14 N during the collision.

Rainbow [258]

Answer:

<em>The change of momentum of the dart is 0.84 Nw.s</em>

Explanation:

<u>Impulse and change of momentum</u>

The change in momentum of an object is its mass times the change in its velocity:

$\Delta p=m\Delta v=m(v_2-v_1)$

The change in the momentum can also be found by considering the force acting on it. If a force F acts for a time Δt, the change of momentum is given by:

$\Delta p=F.\Delta t$

The dart hits a dashboard with a net force of 14 N during the collision and stops in 0.06 seconds. The change of momentum is:

$\Delta p=14*0.06=0.84$

The change of momentum of the dart is 0.84 Nw.s

5 0

3 years ago

Which statements? Please make it quick! I will be disassembled if I do not have the right answer!

Ray Of Light [21]

1
5
and 6 are correct others are wrong horribly wrong

3 0

3 years ago