Answer:
(a) from the anode to the cathode through the external circuit
Explanation:
In an electrochemical cell, there are two half cells; the oxidation half cell and reduction half cell. Oxidation typically refers to loss of electrons and reduction refers to gain of electrons.
Electrons always flow from the anode to the cathode or from the oxidation half cell to the reduction half cell.
The electrical circuit in an electrochemical cell confirms the flow of electron. Usually a light bulb is attached. The correct option is;
(a) from the anode to the cathode through the external circuit
Answer:
hydrochloric acid
Explanation:
The hydrochloric acid in this reaction is the limiting reactant. A limiting reactant is the reactant that is used up in a chemical reaction. It determines the extent of the reaction.
Since the solution indicates a basic one after the end of the reaction, this suggests that more of the sodium hydroxide is still left unreacted with.
The reactant in excess supply here is the sodium hydroxide and the bulk of it is till left in solution.
Answer:
382.5J
Explanation:
<em>Use the formula:</em>
E = mcΔθ or Q = mcΔT
m = 100g
c = 0.45 J/g°C
ΔT or Δθ = 110 - 25 = 85°
<em>Sub in the values:</em>
E = 100 × 0.45 × 85
= 382.5J
When q is the heat energy in joules (J)
so, according to this formula, we can get q (in joule unit):
q = M*C*ΔT
when M is the mass of the water sample = 1.85 g
C is the specific heat capacity of water = 4.18 J/g.°C
and Δ T is the difference in temperature (Tf-Ti) = 33 - 22 = 11°C
So, by substitution, we will get the value of q ( in Joule):
∴ q = 1.85 g * 4.18 J/g.°C * 11 °C
= 85 J
