3 years ago

Question 5 of 25

1 answer:

8 0

Answer:

C Endothermic

Explanation:

a. p. e. x

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bonufazy [111]

Answer:

Final temperature of calorimeter is 25.36^{0}\textrm{C}

Explanation:

Molar mass of anethole = 148.2 g/mol

So, 0.840 g of anethole = $\frac{0.840}{148.2}moles$ of anethole = 0.00567 moles of anethole

1 mol of anethole releases 5539 kJ of heat upon combustion

So, 0.00567 moles of anethole release $(5539\times 0.00567)kJ$ of heat or 31.41 kJ of heat

6.60 kJ of heat increases $1^{0}\textrm{C}$ temperature of calorimeter.

So, 31.41 kJ of heat increases $(\frac{1}{6.60}\times 31.41)^{0}\textrm{C}$ or $4.76^{0}\textrm{C}$ temperature of calorimeter

So, the final temperature of calorimeter = $(20.6+4.76)^{0}\textrm{C}=25.36^{0}\textrm{C}$

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3 years ago