Find the area of a triangle with a base of 14 ft and a height of 11 ft. A = bh/2)

Mathematics

1 answer:

Ilia_Sergeevich [38]2 years ago

7 0

Answer:

Step-by-step explanation:

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Answer:

refer to explanation

Step-by-step explanation:

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In a rhombus, the sides are 14 inches long. two intersecting sides form a 60 degree angle. what are the exact lengths of the two

Klio2033 [76]

Long Diagonal AD = Square Root (2•Side² + 2•Side² • cos(A) )
Long Diagonal AD = Square Root (2*14^2 + 2*14^2 * cos(60) )
Long Diagonal AD = Square Root ( 392 + 392*.5)
Long Diagonal AD = Square Root (392 + 196)
Long Diagonal AD = Square Root (588)
Long Diagonal AD = 24.248711306 

Short Diagonal BC = Square Root (2•Side² - 2•Side² • cos(A) )
Short Diagonal AD = Square Root ( 392 - 392*.5)
Short Diagonal AD = Square Root ( 392 - 196)
Short Diagonal AD = Square Root (196)
Short Diagonal AD = 14

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2 years ago