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2 years ago

Which of the following explains how an executive order differs from a law?

Physics

1 answer:

Novay_Z [31]2 years ago

3 0

Answer:

Executive Orders state mandatory requirements for the Executive Branch, and have the effect of law. They are issued in relation to a law passed by Congress or based on powers granted to the President in the Constitution and must be consistent with those authorities.

Explanation:

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In all measurements and calculations, magnitude (number) and units are always included.

san4es73 [151]

the equation of the line allows us to find the answer is

y = -27.8 t + 97.4

The equation of a line in a linear relationship between two variables, its general expression is

y = A x + B

in this case the slope is the quantity that the independent variable in this case A = -27.8 m / s

The cut-off point that is the value of the dependent variable for x = is b = 97.4 m

In this case we see that the slope has a unit of [m / s] and the dependent variable is a unit of length, therefore the independent variable must have a unit of time [s] so that the entire equation is in units of length

y = -27.8 t + 97.4

[m] = [m / s] [s] + [m]

[m] = [m]

The other two magnitudes with are necessary to write the equation r is the mean square root and gives an idea that the values also fit the line, the best value is 1

In conclusion, the equation of the line allows us to find the answer is

y = -27.8 t + 97.4

learn more about the equation inear here:

brainly.com/question/22851869

8 0

2 years ago

A mass of 0.5 kg hangs motionless from a vertical spring whose length is 1.10 m and whose unstretched length is 0.50 m. Next the

ser-zykov [4K]

Answer:

The maximum length during the motion is $L_{max} = 1.45m$

Explanation:

From the question we are told that

The mass is $m =0.5 kg$

The vertical spring length is $L = 1.10m$

The unstretched length is $L_{un} = 1.30m$

The initial speed is $v_i = 1.3m/s$

The new length of the spring $L_{new} = 1.30 m$

The spring constant k is mathematically represented as

$k = -\frac{F}{y}$

Where F is the force applied $= m * g = 0.5 * 9.8=4.9N$

y is the difference in weight which is $=1.10-0.50=0.6m$

The negative sign is because the displacement of the spring (i.e its extension occurs against the force F)

Now substituting values accordingly

$k = \frac{4.9}{0.6}$

$= 8.17 N/m$

The elastic potential energy is given as $E_{PE} = \frac{1}{2} k D^2$

where D is this the is the displacement

Since Energy is conserved the total elastic potential energy would be

$E_T = initial \ elastic\ potential \ energy + kinetic \ energy$

$E_T = \frac{1}{2} k D_{max}^2 = \frac{1}{2} k D^2 + \frac{1}{2} mv^2$

Substituting value accordingly

$\frac{1}{2} *8.17 *D_{max}^2 =\frac{1}{2} * 8.17*(1.30 - 0.50)^2 + \frac{1}{2} * 0.5 *1.30^2$

$4.085 * D_{max}^2 = 3.69$

$D^2_{max} = 0.9033$

$D_{max} = 0.950m$

So to obtain total length we would add the unstretched length

So we have

$L_{max} = 0.950 + 0.5 = 1.45m$

5 0

2 years ago

Read 2 more answers

Answer the question based on this waveform.

Nuetrik [128]

Answer:

Cannot be determined from the given information

Explanation:

Given the following data;

Velocity = 24 m/s

Period = 3 seconds

To find the amplitude of the wave;

Mathematically, the amplitude of a wave is given by the formula;

x = Asin(ωt + ϕ)

Where;

x is displacement of the wave measured in meters.

A is the amplitude.

ω is the angular frequency measured in rad/s.

t is the time period measured in seconds.

ϕ is the phase angle.

Hence, the information provided in this exercise isn't sufficient to find the amplitude of the waveform.

However, the given parameters can be used to calculate the frequency and wavelength of the wave.

6 0

3 years ago

A miniature quadcopter is located at x = -2.25 m and y, - 5.70 matt - 0 and moves with an average velocity having components Vv,

kupik [55]

Recall that average velocity is equal to change in position over a given time interval,

$\vec v_{\rm ave} = \dfrac{\Delta \vec r}{\Delta t}$

so that the x-component of $\vec v_{\rm ave}$ is

$\dfrac{x_2 - (-2.25\,\mathrm m)}{1.60\,\mathrm s} = 2.70\dfrac{\rm m}{\rm s}$

and its y-component is

$\dfrac{y_2 - 5.70\,\mathrm m}{1.60\,\mathrm s} = -2.50\dfrac{\rm m}{\rm s}$

Solve for $x_2$ and $y_2$ , which are the x- and y-components of the copter's position vector after t = 1.60 s.

$x_2 = -2.25\,\mathrm m + \left(2.70\dfrac{\rm m}{\rm s}\right)(1.60\,\mathrm s) \implies \boxed{x_2 = 2.07\,\mathrm m}$

$y_2 = 5.70\,\mathrm m + \left(-2.50\dfrac{\rm m}{\rm s}\right)(1.60\,\mathrm s) \implies \boxed{y_2 = 1.70\,\mathrm m}$

Note that I'm reading the given details as

$x_1 = -2.25\,\mathrm m \\\\ y_1 = -5.70\,\mathrm m \\\\ v_x = 2.70\dfrac{\rm m}{\rm s}\\\\ v_y=-2.50\dfrac{\rm m}{\rm s}$

so if any of these are incorrect, you should make the appropriate adjustments to the work above.

8 0

3 years ago

The amount of energy which is transported past a given area of the medium per unit of time is known as the ________ of the sound

Aliun [14]

The term that describes the amount of energy transported past a given area of the medium per unit time would be "intensity." In addition, the formula for computing intensity would be:

Intensity = Energy / (Time * Area)

It can be implied that the wave would be more intense when its energy transfer rate gets increased and vibration amplitudes also increases.

6 0

3 years ago